How can I define a user defined function within DynamicModule? For example, if

h[x_] := x^2

I want to find h[2].

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    $\begingroup$ This question is not clear to me; can you give an extended example, please? $\endgroup$ – Mr.Wizard Oct 9 '12 at 20:18
  • $\begingroup$ @Mr.Wizard: Some what like this. DynamicModule[{h[x_] := x^2}, h[2]] so that it can be deployed intp CDF. $\endgroup$ – Jennifer Oct 9 '12 at 20:35

I don't have experience deploying to CDF (version 7), but I don't see anything to stop you from doing:

 h[x_] := x^2;


If this fails perhaps you could explain in what way.

  • $\begingroup$ It works but if there are more than 1 user defined functions $\endgroup$ – Jennifer Oct 9 '12 at 20:55
  • $\begingroup$ @Jennifer then add them just like the first: DynamicModule[{h, i, j} ... `h[x_] := x^2; i[x_] := Sqrt @ x; j[x_] := Sin[x^4]; -- perhaps I still don't understand? $\endgroup$ – Mr.Wizard Oct 9 '12 at 20:59
  • $\begingroup$ It shows error for this DynamicModule[{h, i, j}, h[x_] := x^2; i[x_] := Sqrt@x; j[x_] := Sin[x^4]; h[2], i[3], j[5]] $\endgroup$ – Jennifer Oct 9 '12 at 21:03
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    $\begingroup$ @Jennifer you need to watch your syntax more closely; you accidentally are passing additional arguments to DynamicModule. Try this instead: DynamicModule[{h, i, j}, h[x_] := x^2; i[x_] := Sqrt@x; j[x_] := Sin[x^4]; {h[2], i[3], j[5]} ] $\endgroup$ – Mr.Wizard Oct 9 '12 at 21:04
  • $\begingroup$ Oh yes. Thanks. Now working $\endgroup$ – Jennifer Oct 9 '12 at 21:11

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