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I have this list 

preRowLocalizer[27]={Null, Null, Null, Null, Null, Null, Null, Null, Null, Null, Null, \
Null, Null, Null, Null, Null, Null, Null, Null, Null, Null, {0, 0, 0, 
  0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
   1, 0, 0, 0, 0, 
  0}, Null, Null, Null, Null, Null, Null, Null, Null, Null, Null, \
Null, Null, Null, Null, Null, Null, Null, Null, Null, Null, Null, \
Null, Null, Null, Null, Null}

But I want to get only the element of the form

{0,....,0,1,0,...,0}

I tried using the command Select[preRowLocalizer[27], # != Null], but it is not giving me any output. Does anyone know why this is happening?

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  • 2
    $\begingroup$ Use =!= instead of !=, and report back. $\endgroup$
    – J. M.'s lack of A.I. ♦
    May 29, 2016 at 19:38
  • $\begingroup$ I tried that and it is giving me only an empty set {}. $\endgroup$
    – juyo
    May 29, 2016 at 19:41
  • $\begingroup$ Select[list, # =!= Null &] works for me; what did you put in? $\endgroup$
    – J. M.'s lack of A.I. ♦
    May 29, 2016 at 19:42
  • $\begingroup$ With the additional & works, do you know why that is needed? $\endgroup$
    – juyo
    May 29, 2016 at 19:44
  • $\begingroup$ Look at the docs for Select[]; pay attention to the "Basic Examples". $\endgroup$
    – J. M.'s lack of A.I. ♦
    May 29, 2016 at 19:46

1 Answer 1

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First[DeleteCases[preRowLocalizer[27], Null]]

First[preRowLocalizer[27] /. Null -> Nothing]

First[Cases[preRowLocalizer[27], _List]]

All the above give

{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0}

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