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I am trying to take he derivative of mod(remainder).

In:= D[Mod[x, y], x]
Out = Mod^(1,0)[x,y]

I cannot understand the meaning of Mod^(1,0). What does the exponential actually mean ?

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    $\begingroup$ It means the derivative with respect to the first argument. Look up Derivative[]. $\endgroup$ Commented May 25, 2016 at 17:26
  • $\begingroup$ Look at the FullForm of your result or evaluate D[Mod[x, y], x] // FullForm $\endgroup$
    – Bob Hanlon
    Commented May 25, 2016 at 19:16
  • $\begingroup$ I'm not sure about the "easily found in the documentation" part :) The notation is described explicitly in Derivatives of Unknown Functions. A broader discussion can be found in The Representation of Derivatives. $\endgroup$
    – WReach
    Commented May 26, 2016 at 14:22

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