1
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data={{"0.00mA", "0.18V", "43.1mV"}, {"0.02mA", "0.22V", "55.9mV"}, {"0.03mA", "0.30V", "59.4mV"}, {"0.05mA", "0.33V", "63.6mV"}, {"0.05mA", "0.36V", "79.8mV"}, {"0.07mA", "0.42V", "91.5mV"}, {"0.10mA", "0.54V", "92.6mV"}, {"0.09mA", "0.60V", "91.9mV"}, {"0.00mA", "0.15V", "39.1mV"}, {"0.00mA", "0.18V", "43.1mV"}, {"0.02mA", "0.22V", "55.9mV"}, {"0.03mA", "0.30V", "59.4mV"}, {"0.05mA", "0.33V", "63.6mV"}, {"0.05mA", "0.36V", "79.8mV"}, {"0.07mA", "0.42V", "91.5mV"}, {"0.10mA", "0.54V", "92.6mV"}, {"0.09mA", "0.60V", "91.9mV"}}

I use the following code,but very slow.

Map[QuantityMagnitude@
ReleaseHold@WolframAlpha[#, {{"Input", 1}, "Input"}] &, data, {2}]

How to convert it to a matrix that only contains number?

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  • 1
    $\begingroup$ Is QuantityMagnitude[Map[Interpreter["Quantity"], matrix, {2}]] still too slow for your needs? $\endgroup$
    – J. M.'s eventual burnout ♦
    May 9, 2016 at 14:06
  • $\begingroup$ Good,I intend to use Interpreter["Units"], but found nothing. $\endgroup$
    – partida
    May 9, 2016 at 14:13

2 Answers 2

Reset to default
1
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Map[First@StringCases[#, NumberString] &, data, {2}]

This code can cater my purpose.

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1
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Example:

MatrixForm @ Partition[StringDelete[Flatten @ data, LetterCharacter], 3]

Ex. time: .00010723

Output

output example

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