f [x_] := (x + ln[x] - 3)

Plot[f[x], {x, 0, 5}]

How come this comes out with an empty graph? I tried this and same results: Plot[[x] + ln[x] - 3, {x, 0, 4}]

I'm new to Mathematica and confused why all my graphs come oute mpty

  • 1
    $\begingroup$ Welcome to MSE. You have a syntax error. ln is not a built-in function. Change this to Log[x]. $\endgroup$ – ubpdqn Apr 26 '16 at 5:48
  • $\begingroup$ One way to figure this out is to use free form input. Start by typing =, and it should show an orange equal sign, then if you type "plot x + ln(x) - 3 from 0 to 5" it gives this: i.stack.imgur.com/5hutm.png $\endgroup$ – Jason B. Apr 26 '16 at 6:57

If your plot doesn't show anything, it's often helpful to look what your plotted function does. If you evaluate e.g. f[1] in your notebook, you'll see:

-1 + ln[1]

That's because there is no build-in function called ln. You probably want Log.

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