I've a Boolean gene regulation system composed of vectors(corresponding to cellular phenotypes). Their components are binary numbers such as $\{1,0,0,1\}$. A vector can change its statement in timesteps. For example $\{1,0,0,1\} \longrightarrow \{1,1,0,0\} \longrightarrow \{0,0,1,0\}$, etc.

I know there are several programs doing that but can I draw a vector flow diagram in Mathematica? I mean every vector will correspond to a node(or point) and go to one another. If

$\{1,0,0,1\} = a, \{1,1,0,0\} = b, \{0,0,1,0\} = c$, where $a,b,c$ are constants,

then we have $a \longrightarrow b \longrightarrow c$.

The way above is just what i thought. Maybe there are more efficient ones.

Here is a link of the article containing what I exactly want Figure 2


1 Answer 1


I think this code answers the question:

data = RandomInteger[{0, 1}, {120, 4}];

edges = DirectedEdge @@@ Partition[data, 2, 1];

Graph[edges, VertexLabels -> "Name"]

enter image description here


Because of a question in a comment here is some code that shows the derivation of graphs, spanning trees of those graphs, their disjoint union, and a highlighted connecting path between them. I used disjoint union for clarity (with those random data graphs) -- regular graph union is probably desired with the actual data.

{data1, data2, data3} = 
  Table[RandomInteger[{0, 1}, {n, 4}], {n, {120, 80, 70}}];
{gr1, gr2, gr3} = 
 Map[Graph[DirectedEdge @@@ Partition[#, 2, 1]] &, {data1, data2, 

enter image description here

{tr1, tr2, tr3} = Map[FindSpanningTree[#] &, {gr1, gr2, gr3}]

enter image description here

gr = GraphDisjointUnion[tr1, tr2, tr3, VertexLabels -> "Name"];
connectingEdges = 
  DirectedEdge @@@ 
      Prepend[Length[VertexList[#]] & /@ {gr1, gr2, gr3}, 1]]], 2, 
HighlightGraph[EdgeAdd[gr, connectingEdges], connectingEdges]

enter image description here

  • $\begingroup$ Thank you very much for your quick answer. One more thing, if I have 3 datasets like data1, data2, data3 can I make a tree plot both contain the three data flow(flow scheme)? It will have intersections(overlaps) between datasets. Please have a look at the figure 2 in the article I mentioned. $\endgroup$
    – Haliki
    Commented Apr 22, 2016 at 13:19
  • $\begingroup$ @Haliki I looked into Figure 2 of the linked article. I don't have time to read the article in order to understand how that figure is derived. Please see my question update. $\endgroup$ Commented Apr 22, 2016 at 14:12
  • $\begingroup$ I think GraphLayout -> "LayeredDigraphEmbedding" should select the proper root vertex for a directed tree. If not, it has ` "RootVertex"` suboption. $\endgroup$
    – Szabolcs
    Commented Apr 22, 2016 at 14:23
  • $\begingroup$ Thank you so much for your attention. That worked for me. Best regards. $\endgroup$
    – Haliki
    Commented Apr 25, 2016 at 8:40
  • $\begingroup$ @Haliki Great! I am glad it is working out. $\endgroup$ Commented Apr 25, 2016 at 13:31

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