# Plotting cicle using ListPlot

How can I plot circle plot with ListPlot function or how to organize data to produce circle plot from ListPlot function ?

If u do something like this

ListPlot[Tuples[{{0, 1, 2, 3, 4, 5}, {-3, 3}}]]


i get

{{0, -3}, {0, 3}, {1, -3}, {1, 3}, {2, -3}, {2, 3}, {3, -3}, {3,
3}, {4, -3}, {4, 3}, {5, -3}, {5, 3}}


function value in this example is constant, and we ll see two straight lines.

but, when i need to plot circle, i have two y points per x and they are changing,

so i want plot list plot, i must have data like this:

{{0, f1}, {0, f2}, {1, f1}, {1, f2}, {2, f1}, {2, f2}, {3, f1}, {3,f2}, {4, f1}, {4, f2}, {5, f1}, {5, f2}}


where f1 is y1 and f2 is y2 and

yn = {-Sqrt[R - x^2], Sqrt[R - x^2]}


or, i can make data like this

in = Function[x, {x, (-Sqrt[25 - #1^2]) &[x], (Sqrt[25 - #1^2]) &[x]}] /@
Range[-5, 5, 1/2]
out = {{-5, 0, 0}, {-(9/2), -(Sqrt/2), Sqrt/2},.....


where we have {x1,y1,y2}, but List plot dosent work with this data

So, How can i plot this?

• Are you aware of ListPolarPlot? If so, why do you want to use ListPlot. Also, instead of Pythagoras, you can easily generate x and y from the Cos and Sin of the angle. – Martin Ender Apr 22 '16 at 11:34
• p.s. CirclePoints. – Kuba Apr 22 '16 at 12:13
• Following up on @Kuba's comment, try this: ListPlot[CirclePoints, AspectRatio -> Automatic]. It's a pretty compact way of doing what you ask. Notice the AspectRatio directive in order to produce an undistorted circle. – MarcoB Apr 22 '16 at 14:48

Try this:

    ListPlot[Table[{Cos[a], Sin[a]}, {a, 0, 2 \[Pi], 0.05}],
AspectRatio -> 1]


with the effect of Have fun!

• Thanks, am soo bad at Table, can u tell me how to vary 'a' in ListPointPlot3D[ Table[{5 Cos[fi], 5 Sin[fi], a}, {fi, 0, 2 Pi, Pi/180}]] to produce cylindrical surface – Gelios Apr 22 '16 at 12:17
• @Gelios Table takes more than one iterator as well. Try this for example: ListPointPlot3D[Flatten[Table[{5 Cos[fi], 5 Sin[fi], a}, {fi, 0, 2 Pi, Pi/180}, {a, -1, 1, 0.1}], 1]], which returns this plot. – MarcoB Apr 22 '16 at 14:46
• I see, it works, but i concerned more about data representation, i'm trying threat coordinates line a сartesian product of set(str. line and circle produces cylindrical surf.). And If i use your answer i obtain just work solution with ListPointPlot3D, but if i try this  MatrixForm@ Table[{5 Cos[fi], 5 Sin[fi], a}, {fi, 0, 2 Pi, Pi/180}, {a, -1, 1, 0.1}] it dosent make clear sence, whereas  MatrixForm@Table[{5 Cos[fi], 5 Sin[fi], a}, {fi, 0, 2 Pi, Pi/180}]  is pretty good, but 'a' should changing after one cycle and i can achieve this using AppenTo and For, but It does not look good – Gelios Apr 22 '16 at 15:45
• excuse me, all ok with your solution. – Gelios Apr 22 '16 at 18:55
• @Gelios MatrixForm is for visualization only, not for further calculation or plotting. – Alexei Boulbitch Apr 23 '16 at 9:13

I guess, it will give you the circle: ListPlot[Table[{R Cos[fi],R Sin[fi]},{fi,0,2Pi,Pi/180}],AspectRatio->1]