I'm starting to learn Mathematica. I have to solved this eq and draw the graph. It is developing a series of Taylor in about x0 == 0. This is my equation to solve

This is my equation to solve

eq = 60 - 53 x - 13 x^2 + 5 x^3 + x^4
seq = Solve[eq == 0, x]
f1 = Series[eq, {x, 0, 1}] // Normal

And i have done plot, based on this answer to my previous question. My next step is do 10-order polynomial, but i have to do it by using Table[]. Can you give me short tip how to do this? Although the 1-row, and the rest I will do same.

  • 1
    $\begingroup$ I have edited to your post to include a link to the previous answer you got. Please consider acknowledging help in this way in the future. $\endgroup$ – march Mar 24 '16 at 22:59
eq = 60 - 53 x - 13 x^2 + 5 x^3 + x^4;

g[k_][x_] := Series[eq, {x, 0, k}] // Normal

Since you are doing the series expansion about zero, all expansions with order greater than or equal to 4 will return the original polynomial (eq).

   Tooltip[g[k][x], "k = " <> ToString[k]],
   {k, 0, 4}]],
 {x, -5, 5},
 PlotLegends -> "Expressions"]

enter image description here


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.