I'm starting to learn Mathematica. I have to solved this eq and draw the graph. It is developing a series of Taylor in about x0 == 0. This is my equation to solve

This is my equation to solve

eq = 60 - 53 x - 13 x^2 + 5 x^3 + x^4
seq = Solve[eq == 0, x]
f1 = Series[eq, {x, 0, 1}] // Normal

And i have done plot, based on this answer to my previous question. My next step is do 10-order polynomial, but i have to do it by using Table[]. Can you give me short tip how to do this? Although the 1-row, and the rest I will do same.

  • 1
    $\begingroup$ I have edited to your post to include a link to the previous answer you got. Please consider acknowledging help in this way in the future. $\endgroup$
    – march
    Mar 24, 2016 at 22:59

1 Answer 1

eq = 60 - 53 x - 13 x^2 + 5 x^3 + x^4;

g[k_][x_] := Series[eq, {x, 0, k}] // Normal

Since you are doing the series expansion about zero, all expansions with order greater than or equal to 4 will return the original polynomial (eq).

   Tooltip[g[k][x], "k = " <> ToString[k]],
   {k, 0, 4}]],
 {x, -5, 5},
 PlotLegends -> "Expressions"]

enter image description here


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