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I am working with the finite fields package in Mathematica 9. If I input: 

GF[7, {-2, 0, 0, 1}][{3, 4, 1}]^2

Mathematica gives me $\{4,5,1\}_7$. I want to convert this "field element" to the integer $88$, according to $4\times7^0+5\times7^1+1\times7^2$.

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    $\begingroup$ Have you looked at FromDigits[]? $\endgroup$
    – J. M.'s eventual burnout ♦
    Feb 21, 2016 at 17:19
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    $\begingroup$ I've formatted your question. But I suggest you add a little more info. $\endgroup$
    – QuantumDot
    Feb 21, 2016 at 17:20
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    $\begingroup$ See @J.M. 's answer here. $\endgroup$
    – Michael E2
    Feb 21, 2016 at 17:54

1 Answer 1

Reset to default
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As recommended by J. M. use FromDigits

Needs["FiniteFields`"]

gf = GF[7, {-2, 0, 0, 1}][{3, 4, 1}]^2

enter image description here

FromDigits[Reverse[gf[[1]]], 7]

(*  88  *)
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    $\begingroup$ Just for fun FromDigits[Reverse@#[[1]], #[[0, 1]]] &@gf $\endgroup$
    – user1066
    Feb 21, 2016 at 22:12

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