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So I'd like to complement two associations through shared keys... not the best description, so here's an example:

a = <|"a" -> 1, "b" -> 2, "c" -> 3|>
b = <|"a" -> 1, "b" -> 5|>

The questions is, how b differs from a with respect to common keys only, so c doesn't matter.

And by differs I mean, what minimal example of x fulfills:

<|a, x|> ===  <|a, b|>

I could go with:

Complement @@ Normal@{b, a} // Association
<|"b"->5|>

but stripping associations seems wrong to me. Is there more generic approach?

p.s. in general case one may want to get inf about missing keys too, then:

 Complement @@ Normal @ KeyUnion[{b, a}]
{"b" -> 5, "c" -> Missing["KeyAbsent", "c"]} 
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  • $\begingroup$ Probably wording is not the best so feel free to rename things I've called improperly. $\endgroup$ – Kuba Feb 19 '16 at 12:00
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    $\begingroup$ Let the question stand so as it is, I like 'em and it is anyway a reference. (+1 anyway) $\endgroup$ – user9660 Feb 19 '16 at 13:42
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Complement seems to work without stripping Association in both cases.

Complement[b, a]
(* <|"b" -> 5|> *)

Complement[Sequence @@ KeyUnion[{b, a}]]
(* <|"b" -> 5, "c" -> Missing["KeyAbsent", "c"]|> *)

What version are you using?

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  • $\begingroup$ I don't remember the reason why I've assumed it won't work... Now I feel stupid. :) $\endgroup$ – Kuba Feb 19 '16 at 12:37
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    $\begingroup$ @Kuba Coding fatigue. It happens. $\endgroup$ – Edmund Feb 19 '16 at 13:08

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