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I want to replicate the color scheme colormap/hot from $\LaTeX$ PGF's package pgfplots. The color scheme colormap/hot can be found on p. 189 in the manual. It is defined by

\pgfplotsset{
colormap={hot}{color(0cm)=(blue); color(1cm)=(yellow); color(2cm)=(orange); color(3cm)=(red)}
}

The named colors are from the $\LaTeX$ package xcolor, the manual has a table of named base colors in section 4.1 and additional information, if needed.

The relevant definitions fo the used colors are from the xcolor.sty file:

\definecolorset{rgb/hsb/cmyk/gray}{}{}{
  blue,0,0,1/.66667,1,1/1,1,0,0/.11;
  yellow,0,0,1,0/1,1,0/.16667,1,1/.89;
  orange,1,.5,0/.083333,1,1/0,.5,1,0/.595;
  red,1,0,0/0,1,1/0,1,1,0/.3}

The RGB values are as expected. I think the different colors are blended in a linear fashion.

I want to have a new color scheme, which replicates the above mentioned colormap. If this is not possible, an existing color scheme can be modified. I tried this myself, but could not get a working ColorDataFunction object. With the ColorBar package I was not able to define the color scheme manually, without having to drag control points in the form.

I got as far as this:

ColorData["TemperatureMap"] // FullForm
(* ColorDataFunction["TemperatureMap","Gradients",List[0,1],Function[Blend["TemperatureMap",Slot[1]]]] *)

colfunc=ColorDataFunction["PGFhot", "Gradients", List[0, 1], Blend[Transpose[{{0, 1/3, 2/3, 1}, {Blue, Yellow, Orange, Red}}], #1] &]

But colfunc is apparently no ColorDataFunction.

In the end, I want to use the new color scheme like this:

Plot[x, {x, 0, 1}, 
  ColorFunction -> "Rainbow", 
  PlotLegends -> BarLegend[{ColorData["Rainbow"], {0, 1}}]
]
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    colfunc = Blend[Transpose[{{0, 1/3, 2/3, 1}, {Blue, Yellow, Orange, Red}}], #]&

    Plot[x, {x, 0, 1}, ColorFunction -> colfunc, PlotLegends -> BarLegend[{colfunc, {0, 1}}]]

enter image description here

This is how to simply use a custom color scheme. If you're wanting to have it integrated into MMA in a manner similar to the built in ColorDataFunctions then this is a good question to read through.

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  • $\begingroup$ Thank you. I also tried you definition of colfunc, but I did not name it and tried to use it as a pure function. But I forgot the pair of curly brackets so it would not work. $\endgroup$ – Marco Breitig Feb 12 '16 at 17:37
  • $\begingroup$ Due to the equal spacing, Blend[{Blue, Yellow, Orange, Red}, #] & will also work. $\endgroup$ – J. M. is away♦ Mar 24 '16 at 15:06

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