There is a trial version of Mathematica in the Wolfram website, which can be downloaded for free with a license valid for 15 days. Is this version of Mathematica a "full version"? That is, during these 15 days, will I be able to use all of Mathematica functionality? Or are there some limitations?

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    $\begingroup$ For any official info, you should directly contact WRI or the reseller. $\endgroup$ – Yves Klett Feb 1 '16 at 14:54
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    $\begingroup$ @MarcoB I think that reasoning could apply to all of Mathematica.SE. Any question here could be answered with higher authority by WRI. But I don't think that is the point. The point of a community like this is that we can all learn from our shared experience, which is much more efficient than if we all relied on direct replies from WRI. $\endgroup$ – becko Feb 1 '16 at 18:25
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    $\begingroup$ @becko I disagree. MMA.SE is about applications of the Wolfram language to specific problems. Wolfram will not provide such free consulting services, nor would it necessarily be the best source for such solutions: users continuously extend the capabilities of a language beyond its original design. However, Wolfram is the ultimate source for info on Mathematica as a commercial product, which is what you are after. While implementing an algorithm in FORTRAN, you might ask for help on a forum; if you wanted info on licenses for the Intel FORTRAN compiler, you'd best ask Intel directly. $\endgroup$ – MarcoB Feb 1 '16 at 18:45
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    $\begingroup$ @becko Perhaps more to the point as well, questions on licensing are explicitly off-topic in this forum. See What topics can I ask about here?: "Some kinds of questions are considered off-topic: - Questions on Wolfram Alpha; - Questions on licensing, specific support arrangements, product availability and pre-release versions of Mathematica — please contact Wolfram Support at support@wolfram.com. Questions about the site itself — please ask on the meta site instead." $\endgroup$ – MarcoB Feb 1 '16 at 18:53
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    $\begingroup$ @gwr "But why not including maybe an official answer from WRI so one would have it for further reference? " --> Because at some point in the future the answer would inevitably become obsolete and therefore generate confusion, which would make it worse than useless. $\endgroup$ – MarcoB Feb 1 '16 at 18:54

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