I would like to define an InterpolatingFunction to which data points are transferred as a parameter, e.g.:




However when I’m trying to evaluate or plot function (Plot[f[data,x],{x,h[1],h[Length[data]]}]) Mathematica shows the same error in both cases ReplaceAll::reps: {InterpolatingFunction[…]} is neither a list of replacement rules nor a valid dispatch table, and so cannot be used for replacing. (By three dots I’ve replaced a set of values and options).
Could you suggest what I’m doing wrong?

In the following I want to use f[data,x] for definition of the objective function and minimize it on various 'data' vectors and at a given set of points 'x' (x1,…, xn).

  • $\begingroup$ Do you mean to only sample h at integer steps? $\endgroup$ – IPoiler Jan 26 '16 at 16:52
  • $\begingroup$ Can you be more specific about "both do not work"? How don't they work? Does it spit out errors? Can you provide an example h and an example data set? When you say "minimize it on various data vectors and at a given set of points 'x'", do you mean find the data that minimizes f at a particular x or something else? Please provide more details. $\endgroup$ – march Jan 26 '16 at 16:52
  • $\begingroup$ @march and IPoiler, thanks for your comments, please see the updated OP. $\endgroup$ – Alexander Jan 26 '16 at 17:53
  • $\begingroup$ The error is related to the fact that what you are attempting to use to the right of the /. is not valid. The right of the /. must be either Rules, Associations, or a Dispatch. Interpolation returns an InterpolatingFunction object, which is none of those types, and thus cannot be used with /.. You may want to omit the g[x]/. in that case and just let f be the InterpolatingFunction. $\endgroup$ – IPoiler Jan 26 '16 at 18:12

Functionally, this definition of f works the way I think you're trying to describe your needs:

f[data_, x_] := Interpolation[Table[{h[i], data[[i]]}, {i, 1, Length[data]}], x];

Though, I have reservations about this method with large data vectors because it requires interpolating for every x that's plotted. It'd be better to to create the InterpolatingFunction once for a data set then plot it.

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  • $\begingroup$ Oh, it was that straightforward! Thank you for your help and last comment as well. $\endgroup$ – Alexander Jan 27 '16 at 9:41

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