0
$\begingroup$

How do I call elements of ArrayRules by their indices rather than by Part[ArrayRules[list],i]? I'd like to call the element that looks like {i, j}-> valby referring to the pair {i, j} rather than by a single numerical index denoting the location within the list. The reason for this is I would like to create a new SparseArray based on the elements of a list, but I can't figure out how to change val in ArraryRules while preserving the rules that map it to a SparseArray.

I'd like to call a specific element {i, j} and assign the rules {i, j}-> newval

$\endgroup$
5
  • 2
    $\begingroup$ Can't you just do sparse[[i,j]]=newval...? $\endgroup$ Jan 26, 2016 at 5:54
  • $\begingroup$ @MariusLadegårdMeyer Not for what I'm doing. I'm taking a subset of a list and modifying it and then replacing that part of the original list, so I need to be able to pull individual elements by their indices. $\endgroup$
    – TeeJay
    Jan 26, 2016 at 6:00
  • 3
    $\begingroup$ I'm not sure I follow. Could you add a minimal working example to your question? $\endgroup$ Jan 26, 2016 at 6:52
  • $\begingroup$ @TeeJay, Something like Normal@KeyTake[atest, {{1, 1}, {2, 2}}]? for {1,1} and {2,2} elements as axample? $\endgroup$
    – garej
    Jan 26, 2016 at 19:07
  • $\begingroup$ arrayrules /. ({i, j} -> _) :> {i, j} -> newval or arrayrules /. (idx -> _) :> idx -> newval, where idx is the {i,j} pair? $\endgroup$
    – Michael E2
    Jan 28, 2016 at 12:21

2 Answers 2

3
$\begingroup$

Are you aware that you can define a Rule to specify a change of Rules ?

For example here is a replacement of the value indexed by {1,1} :

{{1, 1} -> 2, {1, 2} -> 3} /.  ({1, 1} -> _) -> ({1, 1} -> XXX)

{{1, 1} -> XXX, {1, 2} -> 3}

$\endgroup$
2
$\begingroup$
(* make a dummy example array *)
test = RandomInteger[10, {5, 5}];

(* get rules *)
atest = ArrayRules[test];

(* Prefix with our replacements - the default behavior *)
(* for sparse array is to ignore subsequent duplicate positions *)

patest = SparseArray[Join[{{1, 1} -> -1, {2, 2} -> -2}, atest]];

(* show result *)
test
patest // Normal

{{1,2,8,2,10},{10,8,6,7,10},{3,1,7,5,8},{8,8,3,0,0},{6,10,4,4,0}}

{{-1,2,8,2,10},{10,-2,6,7,10},{3,1,7,5,8},{8,8,3,0,0},{6,10,4,4,0}}

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.