Let's say I have a rather large adjacency matrix for a partial order relation. Say an 80x80 matrix. What is the best way to display Hasse diagram? I have tried AdjacencyGraph and it does a not so bad job of displaying the graph, but it is definitely not a "good" Hasse diagram. Any help would be greatly appreciated!


I was successfully able to draw the graph using

Hasse = ShowGraph[HasseDiagram[FromAdjacencyMatrix[hasseMatrix, Type -> Directed]]]

after using the information from the answer @Dr.belisarius gave.

  • $\begingroup$ Take a look at HasseDiagram[ ] on the Combinatorica package $\endgroup$ Jan 21, 2016 at 5:27
  • $\begingroup$ reference.wolfram.com/mathematica/Combinatorica/tutorial/… $\endgroup$ Jan 21, 2016 at 5:29
  • $\begingroup$ I have tried to use HasseDiagram[], but for whatever reason it just spits HasseDiagram[insert.graph.here] as output. Perhaps I am not loading Combinatorica correctly? $\endgroup$
    – jix816
    Jan 21, 2016 at 5:40
  • 1
    $\begingroup$ If you work on this, sooner or later you will come across the function TransitiveReductionGraph. I wanted to warn you now that that function is known to be buggy. Check the link to determine whether the bug would affect your results. $\endgroup$
    – Szabolcs
    Jan 21, 2016 at 8:56

1 Answer 1


For example (Partial order here is vertex reachability)

<< Combinatorica`
g = System`RandomGraph[{9, 7}, VertexLabels -> "Name"];
g1 = System`Graph[VertexList@g, DirectedEdge @@@ EdgeList@g]; 
ShowGraph[ HasseDiagram[ MakeGraph[VertexList[g1], 
                        GraphDistance[g1, #1, #2] =!= Infinity &]], VertexNumber -> True]

Mathematica graphics

  • 1
    $\begingroup$ Thank you! This is exactly what I want except I would like to feed in a matrix as the input. This is awesome, though! I wasn't able to get Mathematica to draw HasseDiagrams at all until this example. I was beginning to think it was some sort of installation malfunction, but, alas, it was user error. $\endgroup$
    – jix816
    Jan 21, 2016 at 6:56
  • 2
    $\begingroup$ @jix816 Glad to hear that. May the force ... etc $\endgroup$ Jan 21, 2016 at 7:00

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