# Strange bug: Product[1/(1-1/2^(n-1)),{n,2,Infinity}] = 0?

Bug introduced in 9.0 or earlier and fixed in 11.0.0

This infinite product is correct:

Product[1/(1 - 1/2^n), {n, 1, Infinity}]
(* 1/QPochhammer[1/2, 1/2] *)


Numerical value of this result is not equal to zero

N[1/QPochhammer[1/2, 1/2]]
(* 3.462746619455064 *)


But from following equivalent expression I get a wrong output:

Product[1/(1 - 1/2^(n-1)), {n, 2, Infinity}]
(* 0 *)

• I cannot reproduce your final result, instead obtaining 1/(2 QPochhammer[1/2, 1/2]), as it should be. – bbgodfrey Dec 19 '15 at 17:18
• I can confirm this using: 10.0 for Microsoft Windows (64-bit) with Windows 8.1 – mattiav27 Dec 19 '15 at 17:21
• Which version are you using? – mattiav27 Dec 19 '15 at 17:22
• I get 0/QPochhammer[2, 1/2] on 10.3.1. – b.gates.you.know.what Dec 19 '15 at 17:24
• I get zero under 10.0.1 on OS X10.10.5, but if we change Infinity to some large integer instead, it evaluates correctly. – march Dec 19 '15 at 17:48

\$Version

"10.3.1 for Mac OS X x86 (64-bit) (December 9, 2015)"

p = Product[1/(1 - 1/2^n), {n, 1, Infinity}]

(*  1/QPochhammer[1/2, 1/2]  *)


Error:

Product[1/(1 - 1/2^(n - 1)), {n, 2, Infinity}]

(*  0/QPochhammer[2, 1/2]  *)


Workarounds:

Product[1/(1 - 1/2^(n - 1)), {n, m, Infinity}] /. m -> 2

(*  1/QPochhammer[1/2, 1/2]  *)

Limit[Product[1/(1 - 1/2^(n - 1)), {n, m, Infinity}], m -> 2]

(*  1/QPochhammer[1/2, 1/2]  *)

Product[1/(1 - 1/2^(n - 1)), {n, 2, Infinity}, Regularization -> "Dirichlet"]

(*  1/QPochhammer[1/2, 1/2]  *)