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In my numerical calculations I have a list of Eigenvalues with some of them equal to zero. So, when I calculate the log to the base 2 I get infinity those eigenvalues due to Log[2,0] output.

Question: How can I avoid Log[2,0] in my lengthy code, i.e. to get 0 instead of -Infinity?

Thanks and regards

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    $\begingroup$ What do you want it to be equal to instead? 0? $\endgroup$ – march Dec 13 '15 at 20:39
  • $\begingroup$ @march yes i want it equal to zero instead of infinity $\endgroup$ – Usman Dec 13 '15 at 20:54
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    $\begingroup$ That sounds like a bad idea... $\endgroup$ – Rahul Dec 14 '15 at 0:03
  • $\begingroup$ @Rahul, this would also be the first time I've seen anyone wanting to zero out an infinite logarithm, but there certainly is precedent for zeroing out an infinity: consider the computation of the pseudoinverse from the SVD. Now, whether this zeroing out is appropriate here… is the OP's responsibility. $\endgroup$ – J. M. will be back soon Dec 14 '15 at 3:24
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    $\begingroup$ @Usman, do you think you will ever start to accept the answers to your questions according to the site charter? It helps other users and clean the site queue... $\endgroup$ – garej Dec 14 '15 at 19:15
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Let's assume you want to avoid indeterminate values by replacing them with 0

ClearAll@LogTwo
SetAttributes[LogTwo, {Listable, NumericFunction}]

LogTwo[0 | 0.] := 0
LogTwo[x_?NumericQ] := Log2[x]

list = {1, 0, 2.};

Log[2, list]

{0, -Infinity, 1.}

LogTwo[list]

{0, 0, 1.}

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Another approach is to directly set the unwanted infinities to zero:

list = {1, 0, 2.};
Log[list] /. {Infinity -> 0, -Infinity -> 0}

{0, 0, 0.693147}
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You may use constrain on pattern and use ReplaceAll (/.):

list = {1, 1., 0, 0., 2, 2.}

list /. (x_ /; x > 0) -> Log2[x]

or

list /. x_?Positive -> Log[2, x]

Result:

{0, 0., 0, 0., 1, 1.}

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