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I have a list of numbers data of length 10^7. I have values

rate = 100000.;
cutoff = 2000.;

I try to low pass filter with

LowpassFilter[data
, Quantity[cutoff, "Hz"]
, SampleRate -> Quantity[rate, "Hz"]]

I get the error message:

LowpassFilter::srate: The value of sample rate should be a positive machine-sized integer number or a Quantity representing frequency instead of $Failed.

But if I replace rate with its value, it works fine.

LowpassFilter[data, Quantity[cutoff, "Hz"], 
 SampleRate -> Quantity[100000., "Hz"]]

Why is that, and is there a workaround?

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5
  • 1
    $\begingroup$ The help file says the rate needs to be an integer. Your rate 100000. is a real number. Use an integer 100000 $\endgroup$
    – bill s
    Commented Jun 21, 2021 at 19:47
  • 1
    $\begingroup$ Your first version works for me on Mathematica 12.3. Are you on an earlier version? $\endgroup$
    – mikado
    Commented Jun 21, 2021 at 20:40
  • $\begingroup$ What help file is that? The error message says "The value of sample rate should be a positive machine-sized integer number or a Quantity representing frequency" Mine is the latter. Note also that LowpassFilter does not complain when you use a real number in the quantity. See my second example. $\endgroup$
    – abwatson
    Commented Jun 21, 2021 at 20:42
  • $\begingroup$ I am on 12.3 for Mac OS. $\endgroup$
    – abwatson
    Commented Jun 21, 2021 at 20:43
  • $\begingroup$ The first version works for me on 12.2 on Windows 10. $\endgroup$
    – Derek H
    Commented Jul 23, 2021 at 13:35

1 Answer 1

Reset to default
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No answer to why, but found a work-around. Round the rate value.

LowpassFilter[data, Quantity[cutoff, "Hz"], 
 SampleRate -> Quantity[Round[rate], "Hz"]]
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