I've done a little math and I got the following power series expansion of $\log z$ about $z_0=-2+i$.
$$\log z=\log(-2+i)+\sum_{n=1}^{\infty}\frac{(-1)^{n+1}}{n(-2+i)^n}[z-(-2+i)]^n$$
I've shown that the series converges on $|z-(-2+i)|<\sqrt5$ but I think it only agrees with $\log z$ on $|z-(-2+i)|<1$.
I have:
f = Function[z, Log[-2 + I] +
Sum[(-1)^(n + 1)*(z - (-2 + I))^n/(n*(-2 + I)^n), {n, 1, Infinity}]]
The evaluation
f[-2 + I/2]
produces
log(-2 + I) + log(9/10 + I/5)
I'm wondering if there is an easy way to force this to a logarithm of a single number. I'm also wondering if someone has a suggestion on how to explore the convergence on the two regions defined above.