I want to determine a list, but I'm finding it difficult:
I need a list with the following characteristic:
ClearAll["Global`*"]
a=1.45;b=a*x;c=b*x;d=1;
list={a,b,c,d}
$\left\{1.45,1.45x,1.45x^2,1\right\}$
What would be the value of x?
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1 Answer
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One option is you use the NestList function:
Last[Solve[1.45x^3==1,{x}]]/.Rule->Set;
NestList[#1x&,1.45,3]
$\{1.45,1.28109,1.13185,1.\}$
answered Aug 25, 2017 at 14:00
list[x_] = {a, b, c, d}$\endgroup$