Sort List by first term in case and select cases which certain number in the first term

Question

Suppose I have the following list:

 list = {{1,3.4},{2,6.7},{3,0},{1,2},{2,8.6},{3,7.9},{1,0},{2,7.8},{3,5}};

I will like to sort the list by the first term in the order they are presented on the list like the following:

 {{1,3.4},{1,2},{1,0},{2,6.7},{2,8.6},{2,7.8},{3,0},{3,7.9},{3,5}}.

Finally I will like to make three different list which select the cases starting with certain number as:

list1 = {{1,3.4},{1,2},{1,0}}
list2 = {{2,6.7},{2,8.6},{2,7.8}}
list3 = {{3,0},{3,7.9},{3,5}}

Thanks! It helped for the fist part. Now, how can I create a list with only the cases that start for example by 1? — fermi, Commented Dec 11, 2015 at 21:11
Why doesn't GatherBy[data, First] not solve your problem completely? — m_goldberg, Commented Dec 22, 2015 at 3:15

eldo · Accepted Answer · 2015-12-11 21:28:15Z

2

list = {{1, 3.4}, {2, 6.7}, {3, 0}, {1, 2}, {2, 8.6}, {3, 7.9}, {1, 0}, {2, 7.8}, {3, 5}}

{list1, list2, list3} = GatherBy[list, First];

The more general way is

res = GatherBy[list, First];

and then get a particular part with f.e.

res[[2]]

{{2, 6.7}, {2, 8.6}, {2, 7.8}}

answered Dec 11, 2015 at 21:11

eldo

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$\begingroup$ Thanks! Is there a more general way? I have from 1 to 200. I can write list1, list2,...list200 but it would take long. $\endgroup$
– fermi
Commented Dec 11, 2015 at 21:17
$\begingroup$ see update ------- $\endgroup$
– eldo
Commented Dec 11, 2015 at 21:28

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