1
$\begingroup$

I'm trying to get a result like this:

f[n_, x_] := Abs[((1/Pi)^(1/4) HermiteH[n, x])/(E^(x^2/2) Sqrt[2^n n!])]^2

Plot[Evaluate@Append[Table[f[n, x] + n + 1/2, {n, 0, 7}], x^2/2], {x, -4, 4}, Filling -> gt; Table[n -> gt; n - 1/2, {n, 1, 8}]]

Which gives this.

Only using this code:

a[n_, mu_, delta_] := 1/2*(mu/delta^2*1/(1 + n) - n - 1)

psi[n_, r_, mu_, delta_] := (-1)^n*Pochhammer[2, n]*Exp[-delta*a[n, mu, delta]*r]*(1 - Exp[-delta*r])*Hypergeometric2F1[-n, n + 2*a[n, mu, delta] + 2, 2, 1 - Exp[-delta*r]]

En[n_, mu_, delta_] := -(mu/(2 delta (n + 1)) - 1/2 delta (n + 1))^2

V[r_, mu_, delta_] := -mu*Exp[-delta*r]/(1 - Exp[-delta*r])

cns[n_, mu_, delta_] := 1/Sqrt[(Pochhammer[2, n])^2/(delta*(a[n, mu, delta] + 1)*(2*a[n, mu, delta] + 1)*(2*a[n, mu, delta]))*Sum[Pochhammer[-n, k]*Pochhammer[n + 2*a[n, mu, delta] + 2, k]*Pochhammer[3, k]/(Pochhammer[2, k]*Pochhammer[2*a[n, mu, delta] + 3, k]*k!)*HypergeometricPFQ[{-n, n + 2*a[n, mu, delta] + 2, k + 3}, {2, 2*a[n, mu, delta] + k + 3}, 1], {k, 0, n}]]

npsi[n_, r_, mu_, delta_] := (-1)^n*Pochhammer[2, n]*cns[n, mu, delta]*Exp[-delta*a[n, mu, delta]*r]*(1 - Exp[-delta*r])*Hypergeometric2F1[-n, n + 2*a[n, mu, delta] + 2, 2, 1 - Exp[-delta*r]]



With[{mu = 6^2, delta = 1}, {Plot[Evaluate@Append[Table[npsi[n, r, mu, delta] - (mu/(2 delta (n + 1)) - 1/(2 delta (n + 1)))^2, {n, 1, 4}], V[r, mu, delta]], {r, 0, 5}, PlotRange -> gt; {-80, 1}, Filling -> gt; Axis]}]

(I hope I included all relevant code, let me know if I didn't).

Which gives this at the moment.

I realize I have the filling set to "Axis" but I can't seem to figure out what to put in for it and when I try it keeps giving me an error saying it's not a valid filling interval.

I'm looking for it to fill basically at the energy level for the given wavefunction to the peaks of the wavefunction it's plotting after.

$\endgroup$
1
  • $\begingroup$ I edited your code to replace &s with >'s, because something got messed up in the copy-and-paste, but I think it's still wrong. Can you please check to make sure your code (particularly the parts Filling -> stuff) makes sense? $\endgroup$
    – march
    Commented Dec 8, 2015 at 16:39

1 Answer 1

2
$\begingroup$

something like this?

functionsToPlot[r_, mu_, delta_] := Table[
  N[npsi[n, r, mu, 
     delta] - (mu/(2 delta (n + 1)) - 1/(2 delta (n + 1)))^2],
  {n, 1, 4}
  ]

With[{mu = 6^2, delta = 1},
 Plot[
  {
   V[r, mu, delta],
   Evaluate[functionsToPlot[r, mu, delta]]
   },
  {r, 0, 5},
  PlotRange -> {-82, 1},
  Filling -> {
    2 -> -79,
    3 -> -36,
    4 -> -22,
    5 -> -14
    },
  ImageSize -> Large
  ]
 ]

enter image description here

I defined functionsToPlot just to make the code more clear to read. As a side note, you should avoid variable names starting with an uppercase letter, to prevent unexpected conflicts with built-in symbols.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.