Relative error with bands plot

Question

I have 2 sets of data imported from excel file, Let say A = 20 21 22 ... 30A B= 0 1 2 3 ... 10 I want to plot A with a relative error of 10%

errordataA= Around[A,Scaled[.1]]

But output was "Around[A, Scaled[0.1]]" not "Around[2+-10%]".

Then I want to create a plot with B.

ListPlot[
 {A,
  B
    }
   IntervalMarkers -> "Bands",
 Sequence[PlotTheme -> "Scientific",
  PlotRangePadding -> {Automatic, Scaled[0.15]}]
 ]

Since the code can't read set A data so the graph does not show. How can I fix this one?

Answer 1

The Around expression you mention seems to work fine for me:

a = Around[Range[20, 30], Scaled[0.1]]

(* Out: {Around[20., 2.], Around[21., 2.1], Around[22., 2.2], 
         Around[23., 2.3], Around[24., 2.4], Around[25., 2.5], 
         Around[26., 2.6], Around[27., 2.7], 
         Around[28., 2.8], Around[29., 2.9], 
         Around[30., 3.]} *)

From there, I think you might want to plot a vs. b, i.e. the a values as ordinates and the values as abscissae. If that's what you want, then that works too, but you will want to Transpose the {b, a} set of data:

a = Around[Range[20, 30], Scaled[0.1]]
b = Range[0, 10]

ListPlot[
  Transpose@{b, a},
  IntervalMarkers -> "Bands",
  PlotTheme -> "Scientific",
  PlotRangePadding -> {Automatic, Scaled[0.15]}
]

—-

An alternative interpretation after OP’s comments:

ListPlot[
  {a, b},
  IntervalMarkers -> "Bands",
  PlotTheme -> "Scientific",
  PlotRangePadding -> {Automatic, Scaled[0.15]}
]

Answer 2

For versions prior to v12

Clear["Global`*"]

Needs["ErrorBarPlots`"] // Quiet

a = {1, 0.1} # & /@ Range[20, 30];

b = Range[0, 10];

ErrorListPlot[{a, b},
 PlotRangePadding -> {Automatic, Scaled[0.1]},
 PlotLegends -> {"a", "b"},
 PlotTheme -> "Scientific"]