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Feb 11, 2020 at 9:44 answer added user21 timeline score: 4
Apr 13, 2017 at 12:56 history edited CommunityBot
replaced http://mathematica.stackexchange.com/ with https://mathematica.stackexchange.com/
Nov 16, 2015 at 10:46 comment added mmal I suppose that one solution would be to explicitly call Pardiso solver from Fortran and use LibraryLink. I'll try to experiment with that later today.
Nov 16, 2015 at 9:02 comment added mmal @DanielLichtblau Yes, $A$ is constructed as SparseArray object. @J.M. Yes I've seen that, I'm calling FindRoot with specified Jacobian function FindRoot[F[X], {X, X0}, Method -> {"Newton", "StepControl" -> "LineSearch", "UpdateJacobian" -> 1}, Jacobian :> J[X], AccuracyGoal -> 10, PrecisionGoal -> 10] with F and J a 'black box' functions.
Nov 16, 2015 at 3:11 comment added J. M.'s missing motivation Have you seen this?
Nov 15, 2015 at 22:36 comment added Daniel Lichtblau Is A constructed as an explicit SparseArray? If not, try making it one to see if that improves on memory use and/or LinearSolve speed.
Nov 15, 2015 at 19:37 history tweeted twitter.com/StackMma/status/665976826011996160
Nov 15, 2015 at 17:47 history edited mmal CC BY-SA 3.0
Added links with test case.
Nov 15, 2015 at 17:21 history asked mmal CC BY-SA 3.0