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Nov 14, 2015 at 17:43 comment added m_goldberg @David. This is not a general solution applicable to any array of points. It assumes and takes advantage of the points symmetric arrangement about the origin.
Nov 14, 2015 at 17:16 comment added David @m_goldberg I am wondering about this approach. See my update to my original post.
Nov 14, 2015 at 14:05 comment added J. M.'s missing motivation Slightly shorter: poly = N[ReIm /@ SortBy[z /. sols, N @* Arg]].
Nov 14, 2015 at 13:49 history answered m_goldberg CC BY-SA 3.0