Timeline for Solve equation with sum in it
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| Oct 13, 2015 at 23:52 | history | edited | bbgodfrey | CC BY-SA 3.0 |
improved formatting
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| Oct 13, 2015 at 2:59 | vote | accept | Andrew | ||
| Oct 13, 2015 at 2:33 | answer | added | Bob Hanlon | timeline score: 2 | |
| Oct 13, 2015 at 2:25 | comment | added | Michael E2 |
NSolve[dr == 1/683*10^5 && 700 < t < 800, t, Reals] works, too.
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| Oct 13, 2015 at 2:20 | comment | added | Andrew | @MichaelE2 Yeah, I got the idea, thank for your explanation. | |
| Oct 13, 2015 at 2:19 | comment | added | Michael E2 |
@Andrew If Solve is treating the equation as a polynomial in E^(1/t), then the equation is of degree 10^20+, which is not practically feasible.
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| Oct 13, 2015 at 2:18 | comment | added | Andrew | @Bill I think I got it. Thank you! | |
| Oct 13, 2015 at 2:17 | comment | added | Dr. belisarius | @Andrew Try to solve it by hand and you'll see ... | |
| Oct 13, 2015 at 2:12 | comment | added | Andrew | @Bill Thank you for your help. It worked out. But, why can't we get the result directly by using Solve command? | |
| Oct 13, 2015 at 2:04 | comment | added | Bill | Table[{t, N[dr]-1/683*10^5}, {t,1,1000}] to see why Solve might be having a difficult problem. Then FindRoot[dr - 1/683*10^5, {t, 750}] | |
| Oct 13, 2015 at 1:49 | comment | added | Michael E2 | Welcome to Mathematica.SE! I suggest the following: 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Take the tour! 3) When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign! | |
| Oct 13, 2015 at 1:45 | review | First posts | |||
| Oct 13, 2015 at 2:04 | |||||
| Oct 13, 2015 at 1:41 | history | asked | Andrew | CC BY-SA 3.0 |
