Timeline for How to group the powers of one variable?
Current License: CC BY-SA 3.0
10 events
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| Aug 17, 2012 at 11:56 | comment | added | celtschk |
@xzczd: Note that the internal form (as revealed by FullForm) does not contain Sqrt at all. That's only the way it is displayed. So maybe there's a way to get it displayed differently by changing ToBoxes or Format.
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| Aug 17, 2012 at 11:39 | comment | added | xzczd♦ |
@celtschk then, what if I want to get Sqrt[2 a] x?
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| Aug 17, 2012 at 10:44 | comment | added | celtschk |
@xzczd: That's because Mathematica pulls the factor out during normal evaluation: Sqrt[2 a] evaluates to Sqrt[2] Sqrt[a]. Thus even if Simplify should combine them, you'll never see that because subsequent evaluation will undo it.
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| Aug 17, 2012 at 8:13 | comment | added | xzczd♦ |
Just now, I accidentally found that if b is a certain positive number, Simplify , FullSimplify and Refine won't work 囧: b = 2; Simplify[Sqrt[a x] Sqrt[b x], x > 0 && a > 0], the result is: Sqrt[2] Sqrt[a] x
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| Aug 17, 2012 at 8:00 | comment | added | Vitaliy Kaurov | @xzczd My guess is, in your case, a is left alone and b brought under Sqrt[a] as positive number. | |
| Aug 17, 2012 at 7:54 | comment | added | xzczd♦ |
It seems that when using Simplify and FullSimplify, we can get the result with setting any 2 of the 3 variables as a nonnegative number, for example, {x >= 0, b > 0} is also available, but I don't know the exact reason…
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| Aug 17, 2012 at 7:52 | history | edited | Vitaliy Kaurov | CC BY-SA 3.0 |
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| Aug 17, 2012 at 7:45 | history | edited | Vitaliy Kaurov | CC BY-SA 3.0 |
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| Aug 17, 2012 at 7:38 | review | Low quality posts | |||
| Aug 17, 2012 at 7:43 | |||||
| Aug 17, 2012 at 7:37 | history | answered | Vitaliy Kaurov | CC BY-SA 3.0 |