Timeline for Calculate the Bromwich Integral (Inverse Laplace Transform)
Current License: CC BY-SA 3.0
7 events
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| Sep 21, 2015 at 17:38 | vote | accept | Jan Eerland | ||
| Sep 11, 2015 at 21:45 | comment | added | march |
I'm not sure either solution will end up being very robust. I'm still convinced that InverseLaplaceTransform is best, since it will have the giant look-up table of Laplace-transform pairs, and the OP can look up somewhere what the conditions on the functions are. (I'm still not entirely sure what the OP wants, anyway.) Nonetheless, I found your solution to be clever.
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| Sep 11, 2015 at 21:42 | comment | added | Daniel Lichtblau | @march I actually liked your result more. I just wanted to post something that did not require limits or related. | |
| Sep 11, 2015 at 20:03 | comment | added | march |
@JanEerland. Okay, conditions on c? You can put c back into the expression that he is integrating, and it will spit out no extra condition because c can be anything in your simple case. More generally, if you use this method, and if MMA can do the integral, then it will spit out conditions on whatever constants are in your integrand. You should still specify conditions on a and t in your integral, however, because that is necessary for the definition of the inverse Laplace transform.
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| Sep 11, 2015 at 19:27 | comment | added | Jan Eerland | But it gives not what I expected, because the laplace inverse of $\frac{c}{s}$ is equal to $c$, and I whout like to find the conditions when it becomes $c$ | |
| Sep 11, 2015 at 19:20 | comment | added | march |
Much better than mine! With the Assumptions that a > 0 and t >= 0, this returns exactly 2*Pi. Doing the same thing for the second example in my answer also returns exactly the correct answer. +1
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| Sep 11, 2015 at 18:15 | history | answered | Daniel Lichtblau | CC BY-SA 3.0 |