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How can I calculate the Bromwich Integral in Mathematica? If I enter this as code it gives me just the same:

$$\frac{1}{2\pi i}\int_{\alpha-\infty i}^{\alpha+\infty i} \left(e^{st}\cdot F_{(s)}\right) \text{d}s$$

As example:

I want to calculate the inverse laplace transform of $\frac{c}{s}$:

$$\frac{1}{2\pi i}\int_{\alpha-\infty i}^{\alpha+\infty i} \left(e^{st}\cdot \frac{c}{s}\right) \text{d}s$$

Than it gives me the same back, maybe I've to set some conditions to my code?

My code:

Integrate[Exp[s*t]*c/s, {s, a - Infinity*I, a + Infinity*I}]/(2*Pi*I)

The Bromwich Integral: http://mathworld.wolfram.com/BromwichIntegral.html

How can I calculate the Bromwich Integral in Mathematica? If I enter this as code it gives me just the same:

$$\frac{1}{2\pi i}\int_{\alpha-\infty i}^{\alpha+\infty i} \left(e^{st}\cdot F_{(s)}\right) \text{d}s$$

As example:

I want to calculate the inverse laplace transform of $\frac{c}{s}$:

$$\frac{1}{2\pi i}\int_{\alpha-\infty i}^{\alpha+\infty i} \left(e^{st}\cdot \frac{c}{s}\right) \text{d}s$$

Than it gives me the same back, maybe I've to set some conditions to my code?

My code:

Integrate[Exp[s*t]*(c/s), {s, a - Infinity*I, a + Infinity*I}]/(2*Pi*I)

The Bromwich Integral: http://mathworld.wolfram.com/BromwichIntegral.html

How can I calculate the Bromwich Integral in Mathematica? If I enter this as code it gives me just the same:

$$\frac{1}{2\pi i}\int_{\alpha-\infty i}^{\alpha+\infty i} \left(e^{st}\cdot F_{(s)}\right) \text{d}s$$

As example:

I want to calculate the inverse laplace transform of $\frac{c}{s}$:

$$\frac{1}{2\pi i}\int_{\alpha-\infty i}^{\alpha+\infty i} \left(e^{st}\cdot \frac{c}{s}\right) \text{d}s$$

Than it gives me the same back, maybe I've to set some conditions to my code?

My code:

(1/(2PiI))$\cdot$Integrate[((E^(st))(c/s)), {s, (a-Infinity$\cdot$I), (a+Infinity$\cdot$I)}]

The Bromwich Integral: http://mathworld.wolfram.com/BromwichIntegral.html

How can I calculate the Bromwich Integral in Mathematica? If I enter this as code it gives me just the same:

$$\frac{1}{2\pi i}\int_{\alpha-\infty i}^{\alpha+\infty i} \left(e^{st}\cdot F_{(s)}\right) \text{d}s$$

As example:

I want to calculate the inverse laplace transform of $\frac{c}{s}$:

$$\frac{1}{2\pi i}\int_{\alpha-\infty i}^{\alpha+\infty i} \left(e^{st}\cdot \frac{c}{s}\right) \text{d}s$$

Than it gives me the same back, maybe I've to set some conditions to my code?

My code:

Integrate[Exp[s*t]*c/s, {s, a - Infinity*I, a + Infinity*I}]/(2*Pi*I)

The Bromwich Integral: http://mathworld.wolfram.com/BromwichIntegral.html