Timeline for How to check if a 2D point is in a polygon?
Current License: CC BY-SA 3.0
10 events
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| Oct 11, 2015 at 6:59 | comment | added | matheorem |
@mac p is not right, should be p = CountryData["Canada", "Polygon"][[1, 1,25]];. Because there are 25 parts in Canada. The main part is 25th. Tested in V10
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| S Aug 22, 2012 at 2:26 | history | suggested | CommunityBot | CC BY-SA 3.0 |
formatting
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| Aug 22, 2012 at 2:25 | review | Suggested edits | |||
| S Aug 22, 2012 at 2:26 | |||||
| Aug 15, 2012 at 21:32 | history | edited | Mac | CC BY-SA 3.0 |
Tested all point in polygon routines in terms of speed of execution
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| Aug 14, 2012 at 14:21 | comment | added | user21 | @Mac, you could use a slightly larger polygon (e.g. the polygon from a country from CountryData) and some Random points (with a SeedRandom) and see how that performs ;-) | |
| Aug 14, 2012 at 13:21 | comment | added | J. M.'s missing motivation♦ |
I'd replace the For[] with a Do[] myself...
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| Aug 14, 2012 at 11:48 | comment | added | Mac | Thanks for the suggestion - have updated the code accordingly with i and j now localised. | |
| Aug 14, 2012 at 11:46 | history | edited | Mac | CC BY-SA 3.0 |
deleted 13 characters in body
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| Aug 14, 2012 at 11:26 | comment | added | Mr.Wizard |
Mac, thanks for contributing. Looks interesting! I recommend that you localize i and j.
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| Aug 14, 2012 at 11:22 | history | answered | Mac | CC BY-SA 3.0 |