Timeline for Contourplot fails to plot x==0 if plot range is from 0
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 5, 2015 at 22:21 | history | tweeted | twitter.com/#!/StackMma/status/617820723554451456 | ||
| Jul 3, 2015 at 10:52 | vote | accept | Tom | ||
| Jul 3, 2015 at 7:47 | answer | added | Szabolcs | timeline score: 5 | |
| Jul 2, 2015 at 22:57 | comment | added | march | @Szabolcs. Seems to me that 7 upvotes for a comment warrants an official answer. | |
| Jul 2, 2015 at 14:54 | comment | added | Szabolcs | I do understand that some function are simply not defined outside of the boundary, but for others PlotRange should be a good workaround. | |
| Jul 2, 2015 at 14:54 | comment | added | Tom | Makes sense. Thanks. | |
| Jul 2, 2015 at 14:51 | comment | added | Szabolcs | ContourPlot subdivides the region into smaller and smaller parts to localize the contour. It's a good idea to make sure that any feature you need discovered by ContourPlot should be in the inside of the region, not on the boundary. What is shown in the figure can always be restricted using PlotRange later. Use PlotRange to control what is shown, use the x and y bounds to control what is computed. | |
| Jul 2, 2015 at 14:47 | comment | added | Tom | I am using Mathematica 9.0.0.0 on MAC OS X | |
| Jul 2, 2015 at 14:47 | history | asked | Tom | CC BY-SA 3.0 |