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 2 Reformatted edited Jun 18 '15 at 21:06 Sektor 3,13255 gold badges2121 silver badges3636 bronze badges Try Reduce[x^5 - Sin[x] == 0, x, Reals] Reduce[x^5 - Sin[x] == 0, x, Reals]  or if you want the two roots that are close to -1-1 and 11 you could do something like Table[FindRoot[x^5 - Sin[x] == 0, {x, i}], {i, {-1, 1}}]. Table[FindRoot[x^5 - Sin[x] == 0, {x, i}], {i, {-1, 1}}]  Try Reduce[x^5 - Sin[x] == 0, x, Reals] or if you want the two roots that are close to -1 and 1 you could do something like Table[FindRoot[x^5 - Sin[x] == 0, {x, i}], {i, {-1, 1}}]. Try Reduce[x^5 - Sin[x] == 0, x, Reals]  or if you want the two roots that are close to -1 and 1 you could do something like Table[FindRoot[x^5 - Sin[x] == 0, {x, i}], {i, {-1, 1}}]  1 answered Jun 18 '15 at 20:52 demm 44633 silver badges77 bronze badges Try Reduce[x^5 - Sin[x] == 0, x, Reals] or if you want the two roots that are close to -1 and 1 you could do something like Table[FindRoot[x^5 - Sin[x] == 0, {x, i}], {i, {-1, 1}}].