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Try Reduce[x^5 - Sin[x] == 0, x, Reals]

Reduce[x^5 - Sin[x] == 0, x, Reals] 

or if you want the two roots that are close to -1-1 and 11 you could do something like Table[FindRoot[x^5 - Sin[x] == 0, {x, i}], {i, {-1, 1}}].

Table[FindRoot[x^5 - Sin[x] == 0, {x, i}], {i, {-1, 1}}]

Try Reduce[x^5 - Sin[x] == 0, x, Reals] or if you want the two roots that are close to -1 and 1 you could do something like Table[FindRoot[x^5 - Sin[x] == 0, {x, i}], {i, {-1, 1}}].

Try

Reduce[x^5 - Sin[x] == 0, x, Reals] 

or if you want the two roots that are close to -1 and 1 you could do something like

Table[FindRoot[x^5 - Sin[x] == 0, {x, i}], {i, {-1, 1}}]
1
source | link

Try Reduce[x^5 - Sin[x] == 0, x, Reals] or if you want the two roots that are close to -1 and 1 you could do something like Table[FindRoot[x^5 - Sin[x] == 0, {x, i}], {i, {-1, 1}}].