Timeline for Numerical integration converging too slowly
Current License: CC BY-SA 3.0
18 events
| when toggle format | what | by | license | comment | |
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| Feb 29, 2020 at 20:10 | answer | added | Roman | timeline score: 2 | |
| Feb 29, 2020 at 1:21 | history | edited | bbgodfrey |
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| Nov 26, 2019 at 22:03 | history | edited | bbgodfrey |
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| Jun 21, 2015 at 3:04 | review | First posts | |||
| Jun 21, 2015 at 5:16 | |||||
| Jun 12, 2015 at 14:37 | answer | added | bbgodfrey | timeline score: 9 | |
| Jun 11, 2015 at 19:53 | comment | added | george2079 | ...your integrand has very nearly the symmetry F[x, y]*G[x, y] == - F[x, 2 Pi-y]*G[x,2Pi -y] from which you can show that integral will be zero | |
| Jun 11, 2015 at 18:23 | comment | added | george2079 |
It doesn't actually help in this case, but you should strive to keep your integrand a reasonable magnitude (it is order 10^60.. ). Factor out the constants so the integrand is just F[x,y]*G[x,y]/r (divide by r gets you order 1. ). That said I think your integral actually is zero or nearly so with approximately equal negative and positive parts.
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| Jun 11, 2015 at 17:42 | history | edited | J. M.'s missing motivation♦ |
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| Jun 11, 2015 at 17:23 | comment | added | Deimos | Ok thank you, i edited the first message. It seems that this integral is not a small number how it could be. Maybe i made an error in writing the integrand... | |
| Jun 11, 2015 at 17:22 | history | edited | Deimos | CC BY-SA 3.0 |
added 1400 characters in body
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| Jun 11, 2015 at 17:12 | comment | added | MarcoB | OK, so what are the argument functions? Could you show how you defined them? | |
| Jun 11, 2015 at 17:12 | comment | added | Deimos | i tried also PrecisionGoal -> 1000, MaxRecursion -> 1000, WorkingPrecision -> 2000 | |
| Jun 11, 2015 at 17:11 | comment | added | Deimos | and he told me The precision of the argument function... is less than WorkingPrecision (100.) | |
| Jun 11, 2015 at 17:10 | comment | added | Deimos | i set PrecisionGoal -> 50, MaxRecursion -> 50, WorkingPrecision -> 100 | |
| Jun 11, 2015 at 16:54 | comment | added | MarcoB |
The error explicitly suggests using higher WorkingPrecision. Have you tried doing just that? In particular, my understanding is that you must set WorkingPrecision to be at least as large as PrecisionGoal. Set WorkingPrecision -> 1000?
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| S Jun 11, 2015 at 16:43 | history | suggested | Mahdi | CC BY-SA 3.0 |
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| Jun 11, 2015 at 16:30 | review | Suggested edits | |||
| S Jun 11, 2015 at 16:43 | |||||
| Jun 11, 2015 at 16:20 | history | asked | Deimos | CC BY-SA 3.0 |