Timeline for Computing Reversible CA with CellularAutomaton
Current License: CC BY-SA 3.0
10 events
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May 23, 2016 at 12:59 | history | edited | J. M.'s missing motivation♦ | CC BY-SA 3.0 |
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Jan 15, 2016 at 18:09 | answer | added | arkajad | timeline score: 5 | |
Jun 3, 2015 at 15:16 | history | edited | andandandand | CC BY-SA 3.0 |
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Jun 3, 2015 at 15:14 | comment | added | andandandand | The question is how was the transition function for 150R specified here: "{Mod[Total[Flatten[#]], 2] &, {}, {{-1, 0}, {0, -1}, {0, 0}, {0, 1}}, 2}" Other reversible CA have the same bit-flip behavior when t-1 is 1. | |
Jun 2, 2015 at 18:08 | comment | added | C. E.♦ | Another question then: why can't you solve it? You have an example of how to do what you want to do. What specifically is it that you are having trouble with? Are the rules for other cellular automata more complicated? | |
Jun 2, 2015 at 17:05 | history | edited | andandandand | CC BY-SA 3.0 |
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Jun 2, 2015 at 16:39 | history | edited | andandandand | CC BY-SA 3.0 |
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Jun 2, 2015 at 13:56 | comment | added | andandandand | Oh, the question is how "150" was specified here. The rule is the same as ECA rule 150, flipping the value generated by 150 in t+1 if the cell was '1' in t-1. I'll include this in an image. | |
Jun 2, 2015 at 5:15 | comment | added | C. E.♦ | What is the rule for said cellular automata? It is also not clear to me how it will help you if we implement cellular automata x, it won't be more instructive than the example you already have. | |
Jun 2, 2015 at 3:08 | history | asked | andandandand | CC BY-SA 3.0 |