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Apr 13, 2017 at 12:55 history edited CommunityBot
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Apr 17, 2015 at 20:03 history closed Jens
bbgodfrey
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m_goldberg
ciao
Duplicate of Complex valued 2+1D PDE Schrödinger equation, numerical method for `NDSolve`?
Apr 17, 2015 at 18:10 history edited m_goldberg CC BY-SA 3.0
Routine clean-up
Apr 17, 2015 at 16:24 review Close votes
Apr 17, 2015 at 20:03
Apr 16, 2015 at 17:20 comment added Jens If the link in my previous comment answers your question, then I think the question can be closed. The second part is Taylor's formula: $\exp(a \partial/\partial x) f(x) = f(x+a)$.
Apr 16, 2015 at 17:01 comment added Jens For the second part of the question, I assume you want a more general operator $\exp(\alpha \partial/\partial \theta)$, because without the additional parameter $a$ the expression would be pretty useless. One could see that part as a duplicate of Exponential of a Differential Operator. But if you could be more specific about the actual problem and your solution attempts, there may be a way to give a more specific answer, too.
Apr 16, 2015 at 16:46 history edited SquareRoot2 CC BY-SA 3.0
added 6 characters in body
Apr 16, 2015 at 16:42 answer added 2012rcampion timeline score: 1
Apr 16, 2015 at 16:42 comment added Jens So then you want something like this, right? Complex valued 2+1D PDE Schroedinger equation, numerical method for NDSolve?
Apr 16, 2015 at 16:40 comment added SquareRoot2 @Jens, Starting with a solution of the time-independent problem, one can propagate it in time using $\exp (- \mathrm{i} H t / \hbar)$ to obtain $\psi(t)$, so the problems are related. If you want, equivalently, you can find $\psi (t)$ directly from the time-dependent equation and compute $\langle \theta \rangle$. Note: I'm not trying to solve the TISE, I'm just trying to evolve a given wave packet which is NOT necessarily a solution of the TISE (read as eigenstate of $H$).
Apr 16, 2015 at 16:35 comment added 2012rcampion Shouldn't it be $\exp(\partial_x)\left\{x^2\right\} = 1 + 2x + x^2$?
Apr 16, 2015 at 16:35 comment added Jens This is a time-independent problem, and your first link is to a time-dependent solution. They are very different problems. Also the link doesn't use the time-ordering operator (although it's mentioned), it just discretizes time. If you want to a time-dependent 2D problem, see this link.
Apr 16, 2015 at 16:23 history edited SquareRoot2 CC BY-SA 3.0
Clarified question about dangling exponential.
Apr 16, 2015 at 15:58 comment added user9660 Welcome to Mathematica.SE! I suggest the following: 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Read the faq! 3) When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign!
Apr 16, 2015 at 15:44 review First posts
Apr 16, 2015 at 15:58
Apr 16, 2015 at 15:40 history asked SquareRoot2 CC BY-SA 3.0