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Feb 22, 2015 at 16:48 comment added Jinxed Well, so I seem to have missed your point. :(
Feb 22, 2015 at 11:20 vote accept Kar
Feb 22, 2015 at 11:04 answer added ubpdqn timeline score: 4
Feb 22, 2015 at 9:45 answer added Jinxed timeline score: 2
Feb 22, 2015 at 9:23 comment added Kar @rasher Sorry. I was hoping to have the binomial as either C(9999999, x) or variants of it whilst using fractions whenever relevant.
Feb 22, 2015 at 9:19 comment added ciao Perhaps you need to clarify what you're after. Do you want the binomial to be 9999999,x?
Feb 22, 2015 at 9:12 comment added Kar @rasher Well, not entirely. TraditionalForm evaluates (1/2^24)^x to 16777216^-x whereas HoldForm doesn't use a C notation but outputs Binomial[10000000-1, x]. I wonder if there's some kind of merge of the two? :)
Feb 22, 2015 at 8:21 comment added ciao HoldForm[Binomial[(10000000 - 1), x]*(1/2^24)^x] // TraditionalForm does not do what you're after?
Feb 22, 2015 at 8:18 comment added Kar @rasher Thanks. Is there a way to leave the output as fractions as well? TraditionalForm seems to evaluate the fractions.
Feb 22, 2015 at 7:26 comment added ciao Take a look at TraditionalForm (and HoldForm in combination if you don't want evaluation)
Feb 22, 2015 at 7:08 history asked Kar CC BY-SA 3.0