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How can I partition a list into partitions whose sizes vary? The length of the $$k$$'th partition is a function $$f(k)$$.

For example: if $$l = \{1, 2, 3, 4, 5, 6\}$$ and $$f(k) = k$$. Then the partitioning $$p$$ would look like $$p = \{\{1\},\{2, 3\},\{4,5,6\}\}$$

In Mathematica 11.2, the builtin TakeList will do this.

How can I partition a list into partitions whose sizes vary? The length of the $$k$$'th partition is a function $$f(k)$$.

For example: if $$l = \{1, 2, 3, 4, 5, 6\}$$ and $$f(k) = k$$. Then the partitioning $$p$$ would look like $$p = \{\{1\},\{2, 3\},\{4,5,6\}\}$$

How can I partition a list into partitions whose sizes vary? The length of the $$k$$'th partition is a function $$f(k)$$.

For example: if $$l = \{1, 2, 3, 4, 5, 6\}$$ and $$f(k) = k$$. Then the partitioning $$p$$ would look like $$p = \{\{1\},\{2, 3\},\{4,5,6\}\}$$

In Mathematica 11.2, the builtin TakeList will do this.

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# Partitioning with varying partition size

How can I partition a list into partitions whose sizes vary? The length of the $$k$$'th partition is a function $$f(k)$$.

For example: if $$l = \{1, 2, 3, 4, 5, 6\}$$ and $$f(k) = k$$. Then the partitioning $$p$$ would look like $$p = \{\{1\},\{2, 3\},\{4,5,6\}\}$$