I am plotting polar curves and i tried plotting a parabola $\frac{2}{1-\cos x}$ and $\sec x$

Obviously there are two exclusions $\cos x=1$ and $\cos x=0$

  I dont know how to state multiple exclusions for the same function or variable, i tried these but got error every time...

PolarPlot[{2/(1 - Cos[x]), Sec[x]}, {x, 0, 2 [Pi]}, Exclusions -> {Cos[x] == 0, 1}]

PolarPlot[{2/(1 - Cos[x]), Sec[x]}, {x, 0, 2 [Pi]}, Exclusions -> {x == 0, 2 [Pi], [Pi]/2, (3 [Pi])/2}]

PolarPlot[{2/(1 - Cos[x]), Sec[x]}, {x, 0, 2 [Pi]}, Exclusions -> {Cos[x] == 0, Cos[x]==1}]

What is the right way to do this?

Any help appreciated. Thank you.

I am plotting polar curves with PolarPlot and I tried plotting a parabola with $\frac{2}{1-\cos x}$ and $\sec x$.

Obviously there are two singularities that have to be considered, $\cos x=1$ and $\cos x=0$. I dont know how to specify multiple singularities for the same function or variable. This is what I have tried so far:

PolarPlot[{2/(1 - Cos[x]), Sec[x]}, {x, 0, 2 \[Pi]}, 
 Exclusions -> {Cos[x] == 0, 1}]

PolarPlot[{2/(1 - Cos[x]), Sec[x]}, {x, 0, 2 \[Pi]}, 
 Exclusions -> {x == 0, 2 \[Pi], \[Pi]/2, (3 \[Pi])/2}]

PolarPlot[{2/(1 - Cos[x]), Sec[x]}, {x, 0, 2 \[Pi]}, 
 Exclusions -> {Cos[x] == 0, Cos[x]==1}]

What is the right way to do this?

Any help appreciated. Thank you.