Timeline for Calculate expected value of piece-wise pdf
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
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| S Oct 23, 2014 at 2:14 | history | suggested | A.G. | CC BY-SA 3.0 |
Second condition should be (...) < 3/2 as per OP's comment.
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| Oct 23, 2014 at 2:14 | vote | accept | Wyvern666 | ||
| Oct 23, 2014 at 2:09 | answer | added | Andy Ross | timeline score: 5 | |
| Oct 23, 2014 at 2:01 | history | tweeted | twitter.com/#!/StackMma/status/525104676279050240 | ||
| Oct 23, 2014 at 1:47 | review | Suggested edits | |||
| S Oct 23, 2014 at 2:14 | |||||
| Oct 23, 2014 at 1:38 | answer | added | A.G. | timeline score: 3 | |
| Oct 23, 2014 at 1:18 | comment | added | Nasser |
Just use Plot. I just typed DiscretePlot cause I was looking at example. Once you have Distribution, you can use Mean on it. As in Mean[D0] gives 3/4 There is also expectation, reference.wolfram.com/language/ref/Expectation.html
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| Oct 23, 2014 at 1:07 | comment | added | Wyvern666 | @Nasser It is supposed to be the pdf of a continous random variable, why the discrete plot?. The thing is how to pass that to ExpectedValue[]? | |
| Oct 23, 2014 at 1:03 | comment | added | Nasser |
hum.. Should not your function be Piecewise[{{1, 0 < x < 1/2 || 1 < x < 3/2}, {0, True}}] ? Otherwise, looks ok. Try it, like this D0 = ProbabilityDistribution[Piecewise[{ {1, 0 < x < 1/2 || 1 < x < 3/2}, {0, True}}], {x, -Infinity, Infinity}]; then you can plot it. DiscretePlot[Evaluate[CDF[D0, x], {x, -10, 10}]], etc... see help for more information.
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| Oct 23, 2014 at 0:52 | comment | added | Wyvern666 |
@Nasser This is ok?: ProbabilityDistribution[ Piecewise[{{1, 0 < x < 1/2 || 1 < x < 3/2}, {0, false}}], {x, -Infinity, Infinity}]
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| Oct 23, 2014 at 0:46 | comment | added | Nasser | This is a function definition. Not PDF. Check how to define own PDF here reference.wolfram.com/language/ref/ProbabilityDistribution.html | |
| Oct 23, 2014 at 0:43 | comment | added | Wyvern666 |
@belisarius Yes, like this: Piecewise[{{1, 0 < x < 1/2 || 1 < x < 3/2}, {0, false}}]. The problem is that i dont know how to pass that to ExpectedValue[]
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| Oct 23, 2014 at 0:37 | comment | added | Dr. belisarius | First ...How to write that PDF in Mathematica? Have you tried? | |
| Oct 23, 2014 at 0:32 | history | asked | Wyvern666 | CC BY-SA 3.0 |