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This is a math problem I came across the other day:

$365$ can be written as a sum of two and also three consecutive perfect squares:

$365=14^2+13^2=12^2+11^2+10^2$

$$365=14^2+13^2=12^2+11^2+10^2$$ What is the next number with this property? Give the last 4 digits of the number. The The perfect squares cannot be zero.

I would like to know what would be a good way (esp.especially performance-wise) to check allthe first, letslet's say, 1000000,$1000000$ natural numbers if they can be represented in the way above, using Mathematica?

This is a math problem I came across the other day:

$365$ can be written as a sum of two and also three consecutive perfect squares:

$365=14^2+13^2=12^2+11^2+10^2$

What is the next number with this property? Give the last 4 digits of the number. The perfect squares cannot be zero.

I would like to know what would be a good way (esp. performance-wise) to check all first, lets say, 1000000, natural numbers if they can be represented in the way above, using Mathematica?

This is a math problem I came across the other day:

$365$ can be written as a sum of two and also three consecutive perfect squares: $$365=14^2+13^2=12^2+11^2+10^2$$ What is the next number with this property? Give the last 4 digits of the number. The perfect squares cannot be zero.

I would like to know what would be a good way (especially performance-wise) to check the first, let's say, $1000000$ natural numbers if they can be represented in the way above, using Mathematica?

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kirma
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This is a math problem I came across the other day:

$365$ can be written as a sum of two and also three consecutive perfect squares:

$365$ can be written as a sum of two and also three consecutive perfect squares:

$365=14^2+13^2=12^2+11^2+10^2$

$365=14^2+13^2=12^2+11^2+10^2$

What is the next number with this property? Give the last 4 digits of the number. The perfect squares cannot be zero.

What is the next number with this property? Give the last 4 digits of the number. The perfect squares cannot be zero.

I would like to know what would be a good way (esp. performance-wise) to check all first, lets say, 1000000, natural numbers if they can be represented in the way above, using Mathematica?

This is a math problem I came across the other day:

$365$ can be written as a sum of two and also three consecutive perfect squares:

$365=14^2+13^2=12^2+11^2+10^2$

What is the next number with this property? Give the last 4 digits of the number. The perfect squares cannot be zero.

I would like to know what would be a good way (esp. performance-wise) to check all first, lets say, 1000000, natural numbers if they can be represented in the way above, using Mathematica?

This is a math problem I came across the other day:

$365$ can be written as a sum of two and also three consecutive perfect squares:

$365=14^2+13^2=12^2+11^2+10^2$

What is the next number with this property? Give the last 4 digits of the number. The perfect squares cannot be zero.

I would like to know what would be a good way (esp. performance-wise) to check all first, lets say, 1000000, natural numbers if they can be represented in the way above, using Mathematica?

converting the format of question from image into a text
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This is a math problem I came across the other day:

enter image description here$365$ can be written as a sum of two and also three consecutive perfect squares:

$365=14^2+13^2=12^2+11^2+10^2$

What is the next number with this property? Give the last 4 digits of the number. The perfect squares cannot be zero.

I would like to know what would be a good way (esp. performance-wise) to check all first, lets say, 1000000, natural numbers if they can be represented in the way above, using Mathematica?

This is a math problem I came across the other day:

enter image description here

I would like to know what would be a good way (esp. performance-wise) to check all first, lets say, 1000000, natural numbers if they can be represented in the way above, using Mathematica?

This is a math problem I came across the other day:

$365$ can be written as a sum of two and also three consecutive perfect squares:

$365=14^2+13^2=12^2+11^2+10^2$

What is the next number with this property? Give the last 4 digits of the number. The perfect squares cannot be zero.

I would like to know what would be a good way (esp. performance-wise) to check all first, lets say, 1000000, natural numbers if they can be represented in the way above, using Mathematica?

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VividD
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VividD
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