Timeline for How to create a block diagonal matrix by repeating a submatrix $n$ times?
Current License: CC BY-SA 3.0
14 events
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Sep 8, 2014 at 18:58 | comment | added | Michael E2 |
Mainly I was just linking the question -- see "Linked" in column on the right -- so that others might easily find it. Some of the answers there are easily adapted (using ConstantArray[P, n] for the list of matrices), but special cases often also have special solutions.
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Sep 8, 2014 at 18:49 | vote | accept | user33869 | ||
Sep 8, 2014 at 18:48 | comment | added | user33869 | I noticed that thread. Well, it didn't say how to do that $n$ times. | |
Sep 8, 2014 at 18:47 | vote | accept | user33869 | ||
Sep 8, 2014 at 18:49 | |||||
Sep 8, 2014 at 18:44 | vote | accept | user33869 | ||
Sep 8, 2014 at 18:47 | |||||
Sep 8, 2014 at 18:44 | vote | accept | user33869 | ||
Sep 8, 2014 at 18:44 | |||||
Sep 8, 2014 at 18:22 | comment | added | Michael E2 | This seems to be a special case of this question: How to form a block-diagonal Matrix from a list of matrices? | |
Sep 8, 2014 at 17:55 | history | tweeted | twitter.com/#!/StackMma/status/509037281936949248 | ||
Sep 8, 2014 at 17:11 | history | edited | kglr | CC BY-SA 3.0 |
edited title
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Sep 8, 2014 at 16:28 | answer | added | bill s | timeline score: 4 | |
Sep 8, 2014 at 15:49 | answer | added | kglr | timeline score: 8 | |
Sep 8, 2014 at 15:39 | answer | added | Dr. belisarius | timeline score: 5 | |
Sep 8, 2014 at 15:34 | review | First posts | |||
Sep 8, 2014 at 15:38 | |||||
Sep 8, 2014 at 15:30 | history | asked | user33869 | CC BY-SA 3.0 |