Timeline for Delete duplicates in a list, depending on the sequence of numbers
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| May 19, 2012 at 21:14 | vote | accept | Andrew | ||
| May 19, 2012 at 19:39 | comment | added | Andrew |
This is what I want. For list = {{1, 2, 3}, {3, 2, 1}, {2, 1, 3}, {1, 2, 3}};, it gives {{1, 2, 3}, {2, 1, 3}}. Thanks.
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| May 19, 2012 at 19:30 | history | answered | acl | CC BY-SA 3.0 |