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eldo
eldo
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This is not an answer, but, based on chuy's solution, I want to show someone of the advantages of the new V10 Inactive:

(x = Inner[Inactive[Times],
    {{1, 2}, {3, 4}}, {{5, 6}, {7, 8}},
       Inactive[Plus]]) // MatrixForm

enter image description here

Activate[x, Times] // MatrixForm

enter image description here

Activate[x] // MatrixForm

enter image description here

This is not an answer, but, based on chuy's solution, I want to show some of the advantages of the new V10 Inactive:

(x = Inner[Inactive[Times],
    {{1, 2}, {3, 4}}, {{5, 6}, {7, 8}},
       Inactive[Plus]]) // MatrixForm

enter image description here

Activate[x, Times] // MatrixForm

enter image description here

Activate[x] // MatrixForm

enter image description here

This is not an answer, but, based on chuy's solution, I want to show one of the advantages of the new V10 Inactive:

(x = Inner[Inactive[Times],
    {{1, 2}, {3, 4}}, {{5, 6}, {7, 8}},
       Inactive[Plus]]) // MatrixForm

enter image description here

Activate[x, Times] // MatrixForm

enter image description here

Activate[x] // MatrixForm

enter image description here

Source Link
eldo
eldo
  • 83.1k
  • 6
  • 72
  • 202

This is not an answer, but, based on chuy's solution, I want to show some of the advantages of the new V10 Inactive:

(x = Inner[Inactive[Times],
    {{1, 2}, {3, 4}}, {{5, 6}, {7, 8}},
       Inactive[Plus]]) // MatrixForm

enter image description here

Activate[x, Times] // MatrixForm

enter image description here

Activate[x] // MatrixForm

enter image description here