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Dec 14, 2016 at 9:31 history edited J. M.'s missing motivation
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Aug 4, 2014 at 21:21 answer added george2079 timeline score: 2
Aug 4, 2014 at 21:16 comment added Roy Thanks, Actually I dont want the limit but expansion considering $\alpha$ is very large. (i.e $2/ \alpha^2$). Do yo know how?
Aug 4, 2014 at 21:13 comment added george2079 The second is zero: Limit[ Integrate[ Exp[ -alpha Sqrt[x] ], {x, 0, y}] , alpha -> Infinity, Assumptions -> {y > 0}]. The first you probably need to do numerically
Aug 4, 2014 at 21:06 review First posts
Aug 4, 2014 at 21:07
Aug 4, 2014 at 20:58 history asked Roy CC BY-SA 3.0