Timeline for Plot the minimum of a list of functions
Current License: CC BY-SA 3.0
34 events
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| Jun 8, 2017 at 0:02 | history | edited | Mr.Wizard | CC BY-SA 3.0 |
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| Apr 13, 2017 at 12:56 | history | edited | CommunityBot |
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| Sep 16, 2016 at 0:28 | vote | accept | Moodragonx | ||
| Dec 23, 2015 at 8:22 | vote | accept | Moodragonx | ||
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| Jul 13, 2014 at 21:45 | history | edited | Mr.Wizard | CC BY-SA 3.0 |
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| May 26, 2014 at 21:30 | comment | added | Mr.Wizard |
@Moodragonx You can wait to Accept an answer if you like. Also, should it not work with the built-in legend system you can still build a legend from Graphics primitives as Jens did here. Anyway, I hope to see you back here this autumn.
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| May 26, 2014 at 20:48 | comment | added | Moodragonx | @Mr.Wizard I am currently away from a machine with Mathematica on it and will not have access until the next semester begins in the fall. In the meantime I'm not really sure what to pick as a "best answer" as I've not yet seen if your method works with a legend for a non-buggy version of Mathematica. | |
| May 16, 2014 at 17:38 | comment | added | Mr.Wizard | @Moodragonx Apparently the problem is a bug in version 9.0.0. Can you confirm that is what you are using? | |
| May 16, 2014 at 17:30 | comment | added | Mr.Wizard | @Rahul A little late but interesting nevertheless. Please post any further observations here. Thanks. :-) | |
| May 16, 2014 at 17:23 | comment | added | user484 | Interesting news: Both definitions work fine on Mathematica 9.0.1.0 on Linux. My previous comments were on Mathematica 9.0.0.0 on Mac. | |
| May 16, 2014 at 16:53 | comment | added | Moodragonx | @RahulNarain Ah, yes I removed the BaseStyle -> {14, Thick}, to conceal the fact that the other functions are still being plotted at 0. Perhaps not the best solution since there are times when the x-axis won't align with y=0, and just that it seems inelligent. But using Indeterminate seems to force no other functions to be plotted on those intervals. | |
| May 16, 2014 at 16:47 | comment | added | user484 | @Mr.Wizard: I see the same behaviour as Moodragonx's last two comments, presumably because we're on the same version of Mathematica. However, instead of the curves stopping they drop to zero: i.sstatic.net/J5AIb.png | |
| May 16, 2014 at 16:42 | comment | added | Moodragonx | @Mr.Wizard Hmm... neither version of prep currently work for me (I am on Mathematica 9.0 if that is elucidating), but the form I cited before does. | |
| May 16, 2014 at 16:41 | comment | added | Mr.Wizard | @Rahul You too, please, if you have time. | |
| May 16, 2014 at 16:41 | comment | added | Mr.Wizard | @Moodragonx Would you please see if the new "for version 8" code works as expected? I wish they hadn't changed things... | |
| May 16, 2014 at 16:40 | comment | added | Mr.Wizard |
@Moodragonx Apparently the changed how both If and Indeterminate behave. I guess you are supposed to use ConditionalExpression now. I'll stick that in my answer too.
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| May 16, 2014 at 16:40 | history | edited | Mr.Wizard | CC BY-SA 3.0 |
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| May 16, 2014 at 16:39 | comment | added | Moodragonx | @Mr.Wizard, i.e. Your middle definition of prep[fn_][a__] := Piecewise[{{#, # == fn[a]}}] & /@ {a}, seems to work for me (when specifying the PlotRange). | |
| May 16, 2014 at 16:36 | comment | added | Moodragonx | Removing the "Indeterminate" parameter in Piecewise (and thus letting the default value of the function settle at 0 where you can not see it over the axes bars) seems to fix the error on my end. Also adding PlotRange -> All seems necessary. | |
| May 16, 2014 at 16:32 | history | edited | Mr.Wizard | CC BY-SA 3.0 |
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| May 16, 2014 at 16:32 | comment | added | user484 | No, that doesn't help either. | |
| May 16, 2014 at 16:29 | comment | added | Mr.Wizard |
@Rahul Please try my "New method" with this: prep[fn_][a__] := Piecewise[{{#, # == fn[a]}}, Indeterminate] & /@ {a}
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| May 16, 2014 at 16:27 | comment | added | user484 |
On my machine Plot seems to give up as soon as any of the functions are Undefined everywhere. So I don't think Piecewise would help. That's why I had to use RegionFunction in my answer.
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| May 16, 2014 at 16:26 | comment | added | Mr.Wizard |
@Rahul Well bollocks. Does Piecewise work for you? I can update my answer to use that instead, though it's a little more verbose.
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| May 16, 2014 at 16:25 | comment | added | user484 | Hmm, your "new method" just gives me a blank plot. (Mathematica 9 on Mac OS X.) | |
| May 16, 2014 at 16:19 | history | edited | Mr.Wizard | CC BY-SA 3.0 |
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| May 16, 2014 at 15:47 | comment | added | Mr.Wizard | @Moodragonx Unsurprising, really. Let me think about how to approach that problem, at least with the tools I have. | |
| May 16, 2014 at 15:45 | comment | added | Moodragonx | Thanks for the clarification. Just thought I'd confirm that PlotLegends -> "Expressions" doesn't provide a separate legend entry for each section of the curve (which I expected since it is still only a single function f[x] being plotted). | |
| May 16, 2014 at 15:41 | comment | added | Mr.Wizard |
@Moodragonx More notes added. Sorry I can't help with the PlotLegends option, at least not directly.
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| May 16, 2014 at 15:40 | history | edited | Mr.Wizard | CC BY-SA 3.0 |
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| May 16, 2014 at 15:28 | comment | added | Mr.Wizard | @Moodragonx You're welcome. | |
| May 16, 2014 at 15:28 | history | edited | Mr.Wizard | CC BY-SA 3.0 |
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| May 16, 2014 at 15:27 | comment | added | Moodragonx | Thank you for the prompt response. This doesn't seem to address the generation of a legend request here, however. Will the PlotLegends option used in my question still work to handle this? Further, being new to mathematica the syntax or methods used here are a little lost on me. I'll read up on this but further explanation of how this works would be awesome and whether I should have a reason to choose one method over the other would be appreciated as well. | |
| May 16, 2014 at 15:20 | history | answered | Mr.Wizard | CC BY-SA 3.0 |
