Timeline for Enter exact rational numbers easily with decimal notation
Current License: CC BY-SA 3.0
6 events
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| Apr 9, 2017 at 14:22 | comment | added | Michael E2 |
@Ruslan I see what you mean. What seems simpler depends on context. E.g., how many conversions/entries do you have to do and how often. My personal, and admittedly parochial, experience is limited to infrequent and few conversions. Mostly nowadays they arise from converting parameters in SE questions to exact values, although Rationalize is usually sufficient. It hardly seems simpler to dredge up or write a function, when I can type the fraction in more quickly than I can find and type the function command. But it's different for even a moderate amount of data.
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| Apr 9, 2017 at 13:51 | comment | added | Ruslan |
@MichaelE2 well, that's better, but inconvenient — it's always best to have to change one thing to get what you need. The simplest way would be to define a function, which would do it all for you, as fract in george2079's answer.
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| Apr 9, 2017 at 11:55 | comment | added | Michael E2 | @Ruslan If counting digits is a factor in a particular case, what's simpler than the second option, fractions, in which counting seems unnecessary? | |
| Apr 9, 2017 at 8:41 | comment | added | Ruslan | @MichaelE2 it's not really simplest if you want to be able to append digits (e.g. in a manual binary search): you have to carefully count the digits to make sure your order of magnitude isn't off and that you didn't to forget to change the exponent after you appended a new digit. | |
| Feb 11, 2014 at 23:31 | comment | added | Michael E2 |
I think the OP wants the outputs to be 33333/100000 and 3333/10000 respectively, but I think the simplest way to enter these numbers is 33333*^-5 and 3333*^-4, or as fractions.
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| Feb 11, 2014 at 22:27 | history | answered | user8074 | CC BY-SA 3.0 |
