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S Sep 19, 2016 at 10:13 history suggested LCarvalho CC BY-SA 3.0
I am improved formatting
Sep 19, 2016 at 9:52 review Suggested edits
S Sep 19, 2016 at 10:13
Feb 13, 2014 at 9:18 answer added Alexei Boulbitch timeline score: 1
Feb 12, 2014 at 9:10 vote accept UdiW
Feb 12, 2014 at 5:36 answer added santosh timeline score: 1
Feb 11, 2014 at 22:49 comment added sebhofer @AlexeiBoulbitch Can you elaborate on your comment a bit? I would be interested what you mean with quasi analtytical. Also, how do you know it's not dimensionless?
Feb 11, 2014 at 11:16 comment added UdiW suppose to be power of (n-k) instead of 'n'$$ \text{NIntegrate}\left[\frac{\exp \left(-\frac{x^2}{2 \sigma ^2}\right) \text{NIntegrate}\left[\frac{\exp \left(-\frac{(y-\mu )^2}{2 \sigma ^2}\right)}{\sqrt{2 \pi } \sigma },\{y,x,\infty \}\right]^{n-k}}{\sqrt{2 \pi } \sigma },\{x,-\infty ,\infty \}\right]^k $$
Feb 11, 2014 at 11:15 comment added Alexei Boulbitch And besides, it is recommended to first make it dimensionless. Then you might be able to make it quasi-analytically.
Feb 11, 2014 at 10:40 comment added Yi Wang Nested NIntegrate? NIntegrate[... NIntegrate[...]^n, ...]. And actually the inner one is an erf function, which can be analyticlly integrated.
Feb 11, 2014 at 10:38 review First posts
Feb 11, 2014 at 10:43
Feb 11, 2014 at 10:22 history asked UdiW CC BY-SA 3.0