Timeline for Double integral with variable in the limits
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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S Sep 19, 2016 at 10:13 | history | suggested | LCarvalho | CC BY-SA 3.0 |
I am improved formatting
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Sep 19, 2016 at 9:52 | review | Suggested edits | |||
S Sep 19, 2016 at 10:13 | |||||
Feb 13, 2014 at 9:18 | answer | added | Alexei Boulbitch | timeline score: 1 | |
Feb 12, 2014 at 9:10 | vote | accept | UdiW | ||
Feb 12, 2014 at 5:36 | answer | added | santosh | timeline score: 1 | |
Feb 11, 2014 at 22:49 | comment | added | sebhofer | @AlexeiBoulbitch Can you elaborate on your comment a bit? I would be interested what you mean with quasi analtytical. Also, how do you know it's not dimensionless? | |
Feb 11, 2014 at 11:16 | comment | added | UdiW | suppose to be power of (n-k) instead of 'n'$$ \text{NIntegrate}\left[\frac{\exp \left(-\frac{x^2}{2 \sigma ^2}\right) \text{NIntegrate}\left[\frac{\exp \left(-\frac{(y-\mu )^2}{2 \sigma ^2}\right)}{\sqrt{2 \pi } \sigma },\{y,x,\infty \}\right]^{n-k}}{\sqrt{2 \pi } \sigma },\{x,-\infty ,\infty \}\right]^k $$ | |
Feb 11, 2014 at 11:15 | comment | added | Alexei Boulbitch | And besides, it is recommended to first make it dimensionless. Then you might be able to make it quasi-analytically. | |
Feb 11, 2014 at 10:40 | comment | added | Yi Wang |
Nested NIntegrate? NIntegrate[... NIntegrate[...]^n, ...] . And actually the inner one is an erf function, which can be analyticlly integrated.
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Feb 11, 2014 at 10:38 | review | First posts | |||
Feb 11, 2014 at 10:43 | |||||
Feb 11, 2014 at 10:22 | history | asked | UdiW | CC BY-SA 3.0 |