Timeline for Calling Correct Function for Plotting DiracDelta
Current License: CC BY-SA 3.0
13 events
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| Mar 27, 2012 at 1:22 | history | edited | rm -rf♦ | CC BY-SA 3.0 |
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| Mar 27, 2012 at 1:15 | history | edited | rm -rf♦ | CC BY-SA 3.0 |
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| Mar 26, 2012 at 13:07 | comment | added | acl | @image_doctor Mathematica apparently recognizes that some functions are special and plots them in a special way if you let it; see the middle of this answer for an example of what happens if you do not allow the plotter to see the actual function but only evaluate it numerically: stackoverflow.com/a/6332142/559318 | |
| Mar 26, 2012 at 9:30 | comment | added | image_doctor | This behaviour seems to be associated with the way plot treats points/discontinuities rather than the the underlying function. | |
| Mar 26, 2012 at 9:24 | comment | added | night owl | @R.M: So there is no hope then for a continuous (measure/distribution) plot of the impulse? Only will work for discrete? | |
| Mar 26, 2012 at 9:14 | comment | added | image_doctor | This seems to work with ListPlot and DeltaD set to 10000. ListPlot[DiracD /@ Range[-10, 10], Filling -> Axis]. But Plot seems more stubborn. | |
| Mar 26, 2012 at 9:03 | comment | added | night owl |
@image_doctor: This seems to not work. I used Plot[DiracD[x], {x,-1,1}, PlotStyle:> Thick] to get this: i.sstatic.net/Yh6r8.png
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| Mar 26, 2012 at 9:00 | comment | added | night owl | @R.M: Here is the output graph of the Delta function. i.sstatic.net/VSEr9.png | |
| Mar 26, 2012 at 8:36 | comment | added | image_doctor | You can define your own Dirac Delta function which has the behaviour that you would like. DiracD[x_] := DiracDelta[x] /. DiracDelta[0] -> Infinity . You can swap infinity for any large value that suits your application if you wish. | |
| Mar 26, 2012 at 8:30 | comment | added | rm -rf♦ | Can you show your output plot that you generated in your other program? | |
| Mar 26, 2012 at 8:29 | history | edited | rm -rf♦ | CC BY-SA 3.0 |
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| Mar 26, 2012 at 8:26 | comment | added | night owl | Okay, so what your saying is, is that it cannot be plotted over $\mathbb{R}$? I can accomplish it in another program, but wanted to do it in Mathematica. | |
| Mar 26, 2012 at 8:23 | history | answered | rm -rf♦ | CC BY-SA 3.0 |
