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S Mar 24, 2021 at 21:02 history bounty ended Michael E2
S Mar 24, 2021 at 21:02 history notice removed Michael E2
S Mar 20, 2021 at 21:00 history bounty started Michael E2
S Mar 20, 2021 at 21:00 history notice added Michael E2 Reward existing answer
May 23, 2017 at 8:31 history edited J. M.'s missing motivation
edited tags
Jun 29, 2012 at 11:20 answer added Peter Breitfeld timeline score: 3
May 10, 2012 at 14:31 comment added Daniel Lichtblau Becoming an FAQ hereabouts. Might have a look at this or that or the other.
May 10, 2012 at 7:45 answer added Alexei Boulbitch timeline score: 3
May 10, 2012 at 1:38 history edited rm -rf CC BY-SA 3.0
added 14 characters in body; edited tags; edited title
Mar 25, 2012 at 12:04 history tweeted twitter.com/#!/StackMma/status/183886986363416576
S Mar 25, 2012 at 8:16 history suggested F'x CC BY-SA 3.0
Fix formatting
Mar 25, 2012 at 8:13 review Suggested edits
S Mar 25, 2012 at 8:16
Mar 25, 2012 at 8:05 answer added Andrzej Kozlowski timeline score: 18
Mar 25, 2012 at 4:06 vote accept user001
Mar 25, 2012 at 4:00 answer added FJRA timeline score: 7
Mar 25, 2012 at 3:54 comment added nixeagle Well in your example it does not work as Mathematica is rewriting the whole term inside the log expression as well. Something like this though will do the correct behavior: (x + Log[y*z])/(y*z) /. {z y -> w, 1/(z y) -> w} That is rewrite the y*z to w first and then rewrite the 1/(y*z). Basically you need to remember that Mathematica likes to treat all divisions as multiplications by the inverse.
Mar 25, 2012 at 3:46 answer added rm -rf timeline score: 50
Mar 25, 2012 at 3:45 answer added nixeagle timeline score: 6
Mar 25, 2012 at 3:45 history edited user001 CC BY-SA 3.0
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Mar 25, 2012 at 3:43 comment added CHM The inverse operation can work, that is replacing $\frac{x}{w}$ to $\frac{x}{y*z}$. There must be a way to do it.
Mar 25, 2012 at 3:28 history asked user001 CC BY-SA 3.0