Timeline for Replacing composite variables by a single variable
Current License: CC BY-SA 3.0
21 events
when toggle format | what | by | license | comment | |
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S Mar 24, 2021 at 21:02 | history | bounty ended | Michael E2 | ||
S Mar 24, 2021 at 21:02 | history | notice removed | Michael E2 | ||
S Mar 20, 2021 at 21:00 | history | bounty started | Michael E2 | ||
S Mar 20, 2021 at 21:00 | history | notice added | Michael E2 | Reward existing answer | |
May 23, 2017 at 8:31 | history | edited | J. M.'s missing motivation♦ |
edited tags
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Jun 29, 2012 at 11:20 | answer | added | Peter Breitfeld | timeline score: 3 | |
May 10, 2012 at 14:31 | comment | added | Daniel Lichtblau | Becoming an FAQ hereabouts. Might have a look at this or that or the other. | |
May 10, 2012 at 7:45 | answer | added | Alexei Boulbitch | timeline score: 3 | |
May 10, 2012 at 1:38 | history | edited | rm -rf♦ | CC BY-SA 3.0 |
added 14 characters in body; edited tags; edited title
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Mar 25, 2012 at 12:04 | history | tweeted | twitter.com/#!/StackMma/status/183886986363416576 | ||
S Mar 25, 2012 at 8:16 | history | suggested | F'x | CC BY-SA 3.0 |
Fix formatting
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Mar 25, 2012 at 8:13 | review | Suggested edits | |||
S Mar 25, 2012 at 8:16 | |||||
Mar 25, 2012 at 8:05 | answer | added | Andrzej Kozlowski | timeline score: 18 | |
Mar 25, 2012 at 4:06 | vote | accept | user001 | ||
Mar 25, 2012 at 4:00 | answer | added | FJRA | timeline score: 7 | |
Mar 25, 2012 at 3:54 | comment | added | nixeagle |
Well in your example it does not work as Mathematica is rewriting the whole term inside the log expression as well. Something like this though will do the correct behavior: (x + Log[y*z])/(y*z) /. {z y -> w, 1/(z y) -> w} That is rewrite the y*z to w first and then rewrite the 1/(y*z) . Basically you need to remember that Mathematica likes to treat all divisions as multiplications by the inverse.
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Mar 25, 2012 at 3:46 | answer | added | rm -rf♦ | timeline score: 50 | |
Mar 25, 2012 at 3:45 | answer | added | nixeagle | timeline score: 6 | |
Mar 25, 2012 at 3:45 | history | edited | user001 | CC BY-SA 3.0 |
added 585 characters in body
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Mar 25, 2012 at 3:43 | comment | added | CHM | The inverse operation can work, that is replacing $\frac{x}{w}$ to $\frac{x}{y*z}$. There must be a way to do it. | |
Mar 25, 2012 at 3:28 | history | asked | user001 | CC BY-SA 3.0 |