Timeline for Equating matrices (or higher order tensors) element-wise
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Mar 19, 2012 at 23:06 | vote | accept | yohbs | ||
| Mar 19, 2012 at 22:45 | comment | added | acl |
Yes, I could change 2 to Length@Dimensions[c] to fix that, but there must be a better way
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| Mar 19, 2012 at 22:39 | vote | accept | yohbs | ||
| Mar 19, 2012 at 22:39 | |||||
| Mar 19, 2012 at 22:39 | comment | added | yohbs | Great. How did I not try this first? | |
| Mar 19, 2012 at 22:34 | comment | added | Rojo |
Yeah. RM's second solution is the only "bullet-proof" one so far. Your solution doesn't work for arbitrary dimensional tensors unless you manually change the 2
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| Mar 19, 2012 at 22:29 | comment | added | acl | Right, I see. He has in mind a symbolic matrix on the left hand side, because this does not work for both numerical (also this is what it seems from his motivation). | |
| Mar 19, 2012 at 22:27 | comment | added | Rojo | Yes, to be consistent with what he was doing for matrices | |
| Mar 19, 2012 at 22:26 | comment | added | acl |
this evaluates A==B, then maps Flatten over the result; is this what you intended? (compare Thread[Flatten /@ (a \[Equal] b)] // Trace to the trace of the code I give in my answer to see what I mean)
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| Mar 19, 2012 at 22:22 | history | answered | Rojo | CC BY-SA 3.0 |